Given
subject to the constraint
Let
.
The gradient vectors of
and
are:
and
By Lagrange's theorem, there is a number
, such that
It can be seen that
has local extreme values at the given region.
Answer:
The length of the diagonal is x√10
Step-by-step explanation:
Here, we want to find the length of the diagonal
The diagonal will represent the hypotenuse of a triangle formed with the width and length of the triangle being the measure of the other sides
Mathematically, we then apply Pythagoras’ theorem to get this
we have this as that the square of the diagonal equals the sum of the squares of the two other sides
d^2 = x^2 + (3x)^2
d^2 = x^2 + 9x^2
d^2 = 10x^2
d = √(10x^2)
d = x√10
Answer:
one costs 0.40 and 5 cost 2.00
Step-by-step explanation:
bc 2.80/7 = 0.40
0.40 times 5 = 2.00
Answer:
28
Step-by-step explanation:
Just count the grids
Answer: 20x + 20
Step-by-step explanation: In this problem, the 5 "distributes" through the parentheses, multiplying by each of the terms inside.
So we have 5(4x) + 5(4) which simplifies to 20x + 20.
