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alekssr [168]
3 years ago
14

What is the distance between the points (13,20) and (18,8)

Mathematics
1 answer:
Eva8 [605]3 years ago
6 0
<span>√((18-13)^2+(20-8)^2)=  13
<span>
</span></span>
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Mike made four of his truck payments late and was fined four late fees. If each late fee was $10, how much did he pay in late fe
labwork [276]

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$40, how I got this is I took $10 * 4 late fees and there is your $40

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Kurt spots a bird sitting at the top of a 40 foot tall telephone pole. If the angle of elevation from the ground where he is sta
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Answer:

i guess its 24.03 ft

Step-by-step explanation:

let height of pole be perpendicular length and distance from pole be the base .so tan59=P/b..& b= 24.03ft

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James has 861 feet of rope. There are 14 teams of hikers.
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61.5 Feet of Rope

Step-by-step explanation:

Divide the rope length, 861 feet, by 14 people.

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Tim used the expression n3 to determine the volume of a cube where n represents a side length of the cube. Using this expression
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3 years ago
You want to rent an unfurnished one-bedroom apartment in Boston next year. The mean monthly rent for a random sample of 10 apart
Brilliant_brown [7]

Answer:

90% confidence interval: (2186.53;2881.47)

95% confidence interval: (2118.73;2949.27)

99% confidence interval: (1987.37;3080.63)

For the last part is not the best way say : "This interval describes the price of 95% of the rents of all the unfurnished one-bedroom apartments in the Boston area."

The best interpretation is this one: "We are 95% confident that the actual mean for the rents of unfurnished one-bedroom apartments in the Boston area is between (2118.73;2949.27)"

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=2534 represent the sample mean  

\mu population mean (variable of interest)

\sigma=670 represent the population standard deviation

n=10 represent the sample size  

90% confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Now we have everything in order to replace into formula (1):

2534-1.64\frac{670}{\sqrt{10}}=2186.53    

2534+1.64\frac{670}{\sqrt{10}}=2881.47

So on this case the 90% confidence interval would be given by (2186.53;2881.47)

95% confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

2534-1.96\frac{670}{\sqrt{10}}=2118.73    

2534+1.96\frac{670}{\sqrt{10}}=2949.27

So on this case the 95% confidence interval would be given by (2118.73;2949.27)

99% confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

2534-2.58\frac{670}{\sqrt{10}}=1987.37    

2534+2.58\frac{670}{\sqrt{10}}=3080.63

So on this case the 99% confidence interval would be given by (1987.37;3080.63)

For the last part is not the best way say : "This interval describes the price of 95% of the rents of all the unfurnished one-bedroom apartments in the Boston area."

The best interpretation is this one: "We are 95% confident that the actual mean for the rents of unfurnished one-bedroom apartments in the Boston area is between (2118.73;2949.27)"

7 0
3 years ago
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