Answer:
3x<u>></u><u>=</u><u> </u><u>21</u>
Step-by-step explanation:
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Answer:
Step-by-step explanation:
A circle is inscribed in an equilateral triangle PQR with centre O. If angle OQR = 30°, what is the perimeter of the triangle?
This is a circle inscribed in an equilateral triangle with side s.
If you are asking for the perimeter of PQR, it is 3s.
If you are asking for the perimeter of OQR, it is (3+23–√3)s
Since OR and SR are the hypotenuses of right triangles with adjacent side equal to ½ s, their length is ½s / cos 30° = (√3) /3.
(3/3)s + ((√3) /3)s + ((√3) /3)s = ((3 + 2√3)/3)s ≈ 2.1547s
Hope it helps
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Since this is a triangle all the angles within the triangle add up to 180 degrees so....
82+(9x+2)+(7x)=180
82+2+16x=180
16x+84=180
16x=96
X=6
If we plug in X to angle(9x+2) and angle (7x) we will get 56 and 42. We can get angle 2 by subtracting 180-42 which is 138
FINAL ANSWER: 138 degrees
Step-by-step explanation:
<em>In the second column, we can see that every value of n is being added by 6. </em>
- Thus, the expression is n + 6.
<em>Now, let's substitute the value of n in each column to verify each column. Then, using the expression, let's find the value of n + 6 where n = 28.</em>
<u>When n is 12:</u>
- n + 6 = 18
- 12 + 6 = 18
- 18 = 18
<u>When n is 15:</u>
- n + 6 = 21
- 15 + 6 = 21
- 21 = 21
<u>When n is 21:</u>
- n + 6 = 27
- 21 + 6 = 27
- 27 = 27
<em>Thus, the expression is proven correct. Now, let's find n + 6 when n is 28.</em>
<u>Finding n + 6 when n is 28:</u>
- n + 6 = x
- 28 + 6 = x
- 34 = x
Thus, the missing value in the table is 34.
Answer:
Step-by-step explanation:
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>
