Answer:
x ≤ 3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
2(4 + 2x) ≥ 5x + 5
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Distributive Property] Distribute 2: 8 + 4x ≥ 5x + 5
- [Subtraction Property of Equality] Subtract 5x on both sides: 8 - x ≥ 5
- [Subtraction Property of Equality] Subtract 8 on both sides: -x ≥ -3
- [Division Property of Equality] Divide -1 on both sides: x ≤ 3
So distribute
2x+2+8=6
add like terms
2x+10=6
-10 -10
2x=-4
---------
2. 2
x=-2
Yes, i<span>n mathematics, a </span>rational number<span> is any </span>number<span>that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q.</span>
2x + 4(x - 1) = 2 + 4x
2x + 4x - 4 = 2 + 4x
6x - 4 = 2 + 4x
6x - 4x = 2 + 4
2x = 6
x = 3........there is 1 solution
25 - x = 15 - (3x + 10)
25 - x = 15 - 3x - 10
25 - x = -3x + 5
3x - x = 5 - 25
2x = - 20
x = -20/2
x = -10.....there is 1 solution
4x = 2x + 2x + 5(x - x)
4x = 4x + 5x - 5x
4x = 4x......this has infinite solutions
learn this...
if ur equation ends in a variable equaling a number, then there is one solution.
if ur equation ends in something not equal, like 2 = 4, or 4 = 6, then there is 0 solutions.
if ur equation ends in something equal to something,(the same) like 2 = 2, or 4x = 4x, then there is infinite solutions