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retype in comment and send
Ok so for starters you want to choose an equation and solve for a variable.
So, I am going to choose x from the first equation.
Add y to both sides and you get x=11+y
Next, substitute 11+y for x in the other equation so you get...
2(11+y) +10y=-6
Next distribute the 2 throug the 11 and the y
22+2y+10y=-6
12y=-28
y=-28/12
reduce this fraction to make this easier.
y=-7/3
Now plug in why to either of the equations to find x
x-(-7/3)=11
x+7/3=11
x=11-(7/3)
x=(33/3)-(7/3)
x=26/3
so x = 26/3 and y = -7/3
you can also check to see if this is correct by substituting each of these values into the equations.
What given data? It’s just lines, what’s the data before?
Answer:
35/100
Step-by-step explanation:
You have 12% of horses (10÷84=0.1190 and 0.1190 = 12%)
You have 54% of sheep (54÷84=0.535 and 0.535=54%)
Subtract the amount of Sheep and Horses for the total amount of animals
84-(10+54)
You have 35% of cows (29÷84=0.345 and 0.345=35%)
35% to a fraction is 35/100 (simplified version 7/20)
I hope this helps (:
Answer:
[(2)^√3]^√3 = 8
Step-by-step explanation:
Hi there!
Let´s write the expression:
[(2)^√3]^√3
Now, let´s write the square roots as fractional exponents (√3 = 3^1/2):
[(2)^(3^1/2)]^(3^1/2)
Let´s apply the following exponents property: (xᵃ)ᵇ = xᵃᵇ and multiply the exponents:
(2)^(3^1/2 · 3^1/2)
Apply the following property of exponents: xᵃ · xᵇ = xᵃ⁺ᵇ
(2)^(3^(1/2 + 1/2)) =2^3¹ = 2³ = 8
Then the expression can be written as:
[(2)^√3]^√3 = 8
Have a nice day!
