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Lisa [10]
3 years ago
8

Question 2; how do i solve it?

Mathematics
1 answer:
mestny [16]3 years ago
3 0
Please excuse my dear aunt sally or pemdas
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A countertop is in the shape of a trapezoid. The lengths of the bases are 70.5 and 65.5 inches long. The area of the countertop
const2013 [10]

Answer:

18.

Step-by-step explanation:

We know that the formula to find the height of a trapezoid is: ((a+b)/2)*h.

Using this, we'll get: 18, which is your answer. You can plug in the numbers if you want to confirm this.

Please give brainliest, thank you :)

3 0
2 years ago
Plzz help. Giving everything.<br> D. 24.5
Lemur [1.5K]

Answer:

\frac{8}{14} = \frac{14}{x+2}  (since they're similar, set them up as a proportion to find x)

14*14 = 8(x+2) (cross multiply, solve the left side, and distribute the right side)

196 = 8x +16 (subtract 16 from both sides)

180 = 8x (divide both sides by 8)

x= 22.5 (is your answer, or C)

Step-by-step explanation:

3 0
3 years ago
Angie and Kenny play online video games. Angie buys 1 software package and 3 months of game play. Kenny buys 1 software package
andrey2020 [161]

Answer:The cost of one month of game-play =$20


Step-by-step explanation:

Let the cost of one month of gameplay be x

Then cost of game-play bought by Angie =3x.....(1)

and Then cost of game-play bought by Kenny=4x......(2)

Cost of each software package =$50......(3)

The the total cost =240= sum of costs of software bought by both of them and game-play)=50+50+3x+4x

⇒240=100+7x.......→(by adding like terms)

⇒140=7x⇒x=20.....→( dividing both sides by 7 )

∴the cost of one month of game-play =$20



8 0
3 years ago
Read 2 more answers
WHO DOESN'T LOVE MAX POINTS. MAX POINT QUESTION<br> PLS ANSWER THIS TRIGONOMETRY QUESTION
mezya [45]

Answer:

Solution given:

opposite:9

adjacent: 12

\theta=?

Relationship between opposite and adjacent is given by tan angle

so

Tan \theta=\frac{opposite} {adjacent}=\frac{9}{12}

Tan \theta=\frac{3}{4}

\theta=Tan^{-1}\frac{3}{4}

\bold{\theta=36.8°}

#11.

hypotenuse[h]=11cm

opposite/perpendicular[P]=b cm

adjacent/base[b]=a cm

now

\theta=62°

Relationship between height and hypotenuse is given by Sin angle

:.

Sin 62°=\frac{opposite}{hypotenuse}=\frac{b}{11}

doing crisscrossed multiplication

b=Sin 62°*11

:.b=9.71 cm

a) At <u>9</u><u>.</u><u>7</u><u>1</u><u> </u>cm height does the ladder touch the building.

again

Relationship between base and hypotenuse is given by Cos angle

:.Cos 62°=\frac{base}{hypotenuse}=\frac{a}{11}

doing crisscrossed multiplication

a=Cos 62°×11

a=5.16cm

b) the distance between the foot of the ladder and the building is <u>5.16cm.</u>

4 0
2 years ago
Solve for m. -19m − 19 = 4m − 4m + 19
dangina [55]
-19m-19 = 4m-4m+19
-19m-19 = 0+19
-19m = 19+19
-19m = 38
m = 38÷(-19)
m = -2
7 0
3 years ago
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