All categories

3 years ago

Alvin's age is three times Elgas age. The sum of their ages is 36. What is Elgas age?

Mathematics

1 answer:

olchik [2.2K]3 years ago

3 0

Answer:

Elgas is 9 years old.

Step-by-step explanation:

Alvin: 3 x Elgas

36: Alvin + Elgas

36 / 4 : 9

Elgas: 9

Alvin: 27

To check: 27 + 9= 36

You might be interested in

Anyone know how to solve this?

Dmitry_Shevchenko [17]

Answer:

whats the question..?

Step-by-step explanation:

7 0

3 years ago

Which fraction has the same value as 2 3 8

Alik [6]

Answer:

The Answer : 19/8 Not sure if I'm correct

7 0

3 years ago

Keenan set his watch 3 seconds behind, and it falls behind another

disa [49]

Answer:

in *42* days it will be 45 seconds behind

Step-by-step explanation:

it is already 3 behind and if its only 1 second everyday then you add 1 day until you get to 45 which 42+3 is 45 so the correct answer is 42 days.

6 0

3 years ago

The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

Part C

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

6 0

2 years ago

Idk how to solve these questions

Anuta_ua [19.1K]

Of means multiply

3/5 *n=30

3/5 5/3 cancels than you do 30 *5/3 =50

The answer is 50 you can check your answer by doing 3/5 *50=150/5 or 30 so it's correct .

5 0

3 years ago

Read 2 more answers