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disa [49]
3 years ago
6

A(-3, -2) and B(6, 1), determine the coordinates of point P on directed line segment stack A B with bar on top that partitions s

tack A B with bar on top in a ratio of 2:1
Mathematics
1 answer:
Bad White [126]3 years ago
3 0

Answer:

P(3,0)

Step-by-step explanation:

We want to find the coordinates of P(x,y), that partitions \overline{AB} in the ration m:n=2:1.

where (x_1,y_1)=A(-3,-2) and (x_2,y_2)=B(6,1).

This is given by:

x=\frac{mx_2+nx_1}{m+n}

y=\frac{my_2+ny_1}{m+n}

We substitute the values to get:

x=\frac{2*6+1*-3}{2+1}

x=\frac{9}{3}=3

y=\frac{2*1+1*-2}{2+1}

y=\frac{2-2}{2+1}

y=\frac{0}{3}=0

The coordinates are (3,0)

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Answer:Solve. 2a + 3b = 5 6= a -5 a = 4 b = -1 1 a = 6 b=1 a=6 6 = -1 a=4 6 = 1

Step-by-step explanation:

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Use the Compound Interest formula:     A=P(1+\frac{r}{n})^{nt}       where

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3 years ago
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Step-by-step explanation:

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