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Nataly_w [17]
3 years ago
12

Solve the equation 121x ²+64=0

Mathematics
1 answer:
slava [35]3 years ago
4 0
Hello there ^ _ ^

121x² + 64 = 0
121x² = 0 - 64
121x² = -64
x² = 64/121
Now take square root
x = +/-√-64/121


I hope this help!
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4. Ashley claims that if she triples the side length of a square (s), the area of the square will also be tripled. Do you agree?
stepladder [879]

<u>Answer</u><u> </u><u>:</u><u>-</u>

Let the side of the square measure a cm, thus, according to the question,

  • New length = 3(a cm)

We know that,

➭ Area ( Square ) = a²

Thus, the area of the square with normal length i.e. a cm, will be,

⤳ Area = a x a

⤳ Area = a²

Now, by taking the new length, the area will become,

⤳Area = 3a x 3a

⤳ Area = 9a²

Now,

We observe that, if we divide these, we get,

➤ 9a²/a²

( a² will get canceled since its common )

Thus, the ratio becomes,

➭ 9 : 1 = Area square with tripled length : Area of square

Thus, the area will increase by 9 times, and not 3.

Hence, Ashley's assumptions are wrong.

5 0
3 years ago
Given: mAngleEDF = 120°; mAngleADB = (3x)°; mAngleBDC = (2x)° Prove: x = 24 3 lines are shown. A line with points E, D, C inters
N76 [4]

Answer:

" Vertical angles are congruent " ⇒ 2nd answer

Step-by-step explanation:

* <em>Look to the attached figure </em>

- There are three lines intersected at point D

- We need to find the missing in step 3

∵ Line FA intersects line EC at point D

- The angles formed when two lines cross each other are called

 vertical angles

- Vertical angles are congruent (vertical angles theorem)

∴ ∠ADC and ∠FDE are vertical angles

∵ Vertical angles are congruent

∴ ∠EDF ≅ ∠ADC

∴ m∠EDF ≅ m∠ADC

∵ m∠EDF = 120° ⇒ given

∵ m∠ADC = m∠ADB + m∠BDC

∴ m∠ADB + m∠BDC = 120°

∵ m∠ADB = (3x)° ⇒ given

∵ m∠BDC = (2x)° ⇒ given

∴ 3x + 2x = 120 ⇒ add like terms

∴ 5x = 120 ⇒ divide both sides by 5

∴ x = 24

Column (1)                                                     Column (2)

m∠EDF = 120°                                               given

m∠ADB = 3 x                                                 given

m∠BDC = 2 x                                                 given

∠EDF and ∠ADC are vertical angles           defin. of vert. ∠s

∠EDF is congruent to ∠ADC                        vertical angles are      

                                                                        congruent  

m∠ADC = m∠ADB + m∠BDC                        angle add. post.

m∠EDF = m∠ADC                                          defin. of cong.

m∠EDF = m∠ADB + m∠BDC                         substitution

120° = 3 x + 2 x                                               substitution

120 = 5 x                                                         addition

x = 24                                                              division  

∴ The missing reason is " vertical angles are congruent "

- From the explanation above ∠ADC and ∠FDE are vertical

 angles then they are congruent according to vertical angle

 theorem

6 0
4 years ago
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As Saturn revolves around the sun, it travels at a speed of approximately 6 miles per second. Convert this speed to miles per mi
bekas [8.4K]
Saturn will travel 86,400 miles in 4 minutes.
6 0
4 years ago
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I JUST WANNA PASS MY SOPHOMORE YEAR BUT I SUCK AT MATH!!!!! PLEASE HELP!!!!!!
Natasha2012 [34]

Mr. Sanchez's class: 1.65p

Mr. Kelly's class: 1.36j

where p = fruit pies and j = fruit juice

____________________________________________________________

(a) Creating a system of equations

p + j = 79

1.65p + 1.36j = 118.17

are your system of equations

____________________________________________________________

(a) Solving the system of equations for p and j

Solve for p in the first equation. Subtract j from both sides.

p = 79 - j

____________________________________________________________

Plug p into the second equation.

1.65(79 - j) + 1.36j = 118.17

Distribute 1.65 inside the parentheses.

130.35 - 1.65j + 1.36j = 118.17

Combine like terms.

130.35 - 0.29j = 118.17

Subtract 130.35 from both sides.

-0.29j = -12.18

Divide both sides by -0.29.

j = 42

____________________________________________________________

Plug j into the first equation.

p + (42) = 79

Subtract 42 from both sides.

p = 37

____________________________________________________________

(b) To find out how much each class earned

Now plug in p and j into Mr. Sanchez's class and Mr. Kelly's class equations (at the top).

Mr. Sanchez's class: 1.65(37) = 61.05

Mr. Kelly's class: 1.36(42) = 57.12

____________________________________________________________

(c) To see how much more Mr. S's class earned

Subtract 57.12 from 61.05.

61.05 - 57.12 = 3.93

____________________________________________________________

(a)

p + j = 79

1.65p + 1.36j = 118.17

(b)

Mr. Sanchez's class earned more money (61.05 > 57.12).

(c)

Mr. Sanchez's class earned $3.93 more than Mr. Kelly's class.

3 0
3 years ago
Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2,−3) B(4,−3) C(4,5) D(2,5
AveGali [126]

Answer:

21 unit square

Step-by-step explanation:

First you want to find the length and width of the rectangle using the distance formula:

d=√(x2-x1)²+(y2-y1)²

AB=√(6-3)²+ (-2 - -2)²

AB=√3² + 0

AB=√9

AB=3

BC=√(6-6)²+ (5 - -2)²

BC=√0 + 7²

BC=√49

BC=7

We can find the area by multiplying these two distances together:

A=(3)(7)

A=21 units square.

Hope it helped...... And plz mark BRAINLIEST

Tysm

7 0
3 years ago
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