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3 years ago

(1 - cosx) (1 + 1/cosx) = sinxtanx

Mathematics

1 answer:

Nataly [62]3 years ago

5 0

Answer:

cos x ≠ 0 ⇔ x ≠ $\frac{pi}{2}+k.pi$ ; k ∈ N

$(1-cosx)(1+\frac{1}{cosx})=sinx.tanx\\\\(1-cosx)(\frac{cosx+1}{cosx})=sinx.\frac{sinx}{cosx}\\\\ \frac{1-cos^{2} x}{cosx} =\frac{sin^{2}x }{cosx}\\\\=>1-cos^{2}x=sin^{2}x$

<=> cos²x + sin²x = 1

⇔ 1 = 1

=> x = { R \ (pi/2 + k.pi); k ∈ N}

Step-by-step explanation:

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Indi bought a shirt for $30. He paid 7% sales tax. How much sales tax did Indie pay?

ivann1987 [24]

He paid $ 32.10

because

07 * 30 = 2.10

2.10 + 30 = $ 32.10

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2 years ago

A can in the shape of a right circular cylinder is required to have a volume of 500 cubic centimeters. The top and bottom are ma

borishaifa [10]

Answer:

The answer to the question is

The total cost C of the material as a function of the radius r of the cylinder is

0.6912·r² + 800/r Dollars.

Step-by-step explanation:

To solve the question, we note that

The area of the top and bottom combined = 2·π·r²

The area of the sides = 2·π·r·h

and the volume = πr²h = 500 cm²

Therefore height = 500/(πr²)

Substituting the value of h into the area of the side we have

Area of the side = 2πr·500/(πr²) = 1000/r

Therefore total area of can = Area of top + Area of bottom + Area of side

Whereby the cost of the can = 0.11×Area of top +0.11×Area of bottom +0.8×Area of side

Which is equal to

0.11×2×π×r²+ 0.8×1000/r = 0.6912·r² + 800/r

The cost of the can is $(0.6912·r² + 800/r)

3 0

3 years ago

Which equation can be used to find A, the area of the parallelogram shown? A = 5 × 9 A = 4 × 9 A = 12 × 5 × 9 A = 12 × 4 × 9

Vlada [557]

Answer:

I believe it's A=5 times 9 but since the triangle is special (3-4-5), it could be 12 times 5. Hope this kinda help :)

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3 years ago

Can someone do 11??? Please help I don’t want to fail my class

jolli1 [7]

<h3>Answer: choice A) </h3><h3>tan(Y) = 6/7 and tan(Z) = 7/6</h3>

Recall that the tangent of an angle is equal to the ratio of the opposite over adjacent sides

tan(angle) = opposite/adjacent

For reference angle Y, the opposite side is XZ = 6 and the adjacent side is XY = 7, so,

tan(Y) = XZ/XY = 6/7

For tan(Z), things will swap. The opposite side is now XY = 7 and the adjacent side is now XZ = 6

tan(Z) = XY/XZ = 7/6

We do not use the hypotenuse sqrt(85) at all in this problem because the tangent ratio does not involve the hypotenuse.

4 0

3 years ago

What are the potential solutions of In(x^2-25)=0?

Maslowich

Answer:

$x =\pm \sqrt{26}$

Step-by-step explanation:

Given :-

ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

Equation :-

$\implies log_e {(x^2-25)}= 0$