Answer:
The center of that class, which is the sum of its largest and smallest values divided by 2 ⇒ E
Step-by-step explanation:
* Lets explain what is the class mid-point
- It is defined as the average of the upper and lower class limits
- The class midpoint is the lower class limit plus the upper class limit
divided by 2
- The easiest way to find the class mid-point is to add the upper
and lower boundary and divide your answer by two
- The lower limit for every class is the smallest value in that class.
- The upper limit for every class is the greatest value in that class
* <u><em>Lets solve the problem</em></u>
- It is not the largest value of that class minus the class width
- Its not the difference between the largest and smallest values of
that class
- It is not the difference between the largest and smallest values of
that class divided by 2
- It is the center of that class, which is the sum of its largest and
smallest values divided by 2
Step-by-step explanation:
Hey
Sup
Here is the rough figure of how to construct Quadrilateral TRUE....
Follow this rough diagram and construct the quadrilateral according to it....
HOPE THIS ROUGH DIAGRAM HELPS YOU :)
You can't divide 20 by 8 so you would take away 20
Answer: B
Step-by-step explanation:
We are given that a 45-45-90 triangle has a hypotenuse of 
.
In a 45-45-90 triangle, the legs are congruent. Therefore we can use the Pythagorean Theorem to solve.
[combine like terms]
[square root both sides]
[divide both sides by root 2]
Now, we know that a leg is length 7, which is B.
The correct answer would be C) because 0.40 is 40% of 1.00.
