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jeyben [28]
3 years ago
14

Which option is equal to 7 1/5

Mathematics
2 answers:
masya89 [10]3 years ago
8 0

Answer:

<h2><em><u>D. is the answer</u></em></h2>

Step-by-step explanation:

Question:

7^1/5

The number given has an exponent of a fraction: fraction exponent = 1/5

<h2><em><u>So, when you have a fraction - you always have a square root - Important!!</u></em></h2>

Since the top is one, the number 7 stays the same. = 7^1 = 7

The bottom is a 5. This means it is to the fifth root.

Answer = D

Hope this helped,

Kavitha

lisov135 [29]3 years ago
3 0

Answer: If 36/7 is one of the options, choose that one.

If the question involves an exponent, you should use the "caret" which is ^ found above the 6 on a keyboard. [Shift + 6]. That helps avoid confusion.

Step-by-step explanation: 7 is equal to 35/5 because 7×5=35

Add 1/5 and you end up with 36/5. A Common rational number.

7^(1/5) = the 5th root of 7. A very small irrational number!

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Find the fraction of stundents enrolled in each language
blondinia [14]

Fraction of students enrolled in Chinese = \frac{51}{126}

Fraction of students enrolled in French = \frac{33}{126}

Fraction of students enrolled in Spanish = \frac{42}{126}

Solution:

Total number of students = 51 + 33 + 42

                                          = 126

Number of students enrolled in Chinese = 51

Fraction of students enrolled in Chinese

             $=\frac{\text{Number of students enrolled in Chinese}}{\text{Total number of students}}

             $=\frac{51}{126}

Fraction of students enrolled in Chinese = \frac{51}{126}

Number of students enrolled in French = 33

Fraction of students enrolled in French

             $=\frac{\text{Number of students enrolled in French}}{\text{Total number of students}}

             $=\frac{33}{126}

Fraction of students enrolled in French = \frac{33}{126}

Number of students enrolled in Spanish = 42

Fraction of students enrolled in Spanish

             $=\frac{\text{Number of students enrolled in Spanish}}{\text{Total number of students}}

             $=\frac{42}{126}

Fraction of students enrolled in Spanish = \frac{42}{126}

7 0
3 years ago
A certain family can afford a monthly mortgage payment of $1,340.00. With an APR of 5.25% per annum, what is the maximum mortgag
irina [24]

Answer:

  $198,859.03

Step-by-step explanation:

The amortization formula is good for this. Fill in the given numbers and solve for the unknown.

 A = P(r/n)/(1 -(1 +r/n)^(-nt))

where A is the monthly payment, P is the principal amount of the loan, r is the annual interest rate, n is the number of times per year interest is compounded, and t is the number of years.

  1340.00 = P(0.0525/12)/(1 -(1 +0.0525/12)^(-12·20)) ≈ 0.00673844·P

  P ≈ 1340/0.00673844 ≈ $198,859.03

The family can afford a loan for $198,859.

4 0
3 years ago
How do I convert into pounds
maksim [4K]
The way you convert is by dividing your answer to the question by 1,2or how many they are talking about . Once you do that you will get your answer which may be a decimal and the you put the unit kg for kilograms. so that will be the answer to the problem.
6 0
2 years ago
Write the equation of the line that contains (8,0) and is parallel to the line -3x+4y=4
Kobotan [32]

Answer:

y = (3/4)x - 6

Step-by-step explanation:

if line is parallel to -3x + 4y = 4, that means that they both have the same slope

Slope of that second line is 3/4.

now time to find the y-intercept

0 = 3/4*8 + b

therefore, b = -(3/4)*8 = -3*2 = -6

Therefore, equation of line is y = (3/4)x - 6

7 0
3 years ago
Part 1:
emmasim [6.3K]
Here are my answers to the given questions above:
Part 1. Here is my example of a real life scenario that describes what is happening. Let us say, I have 2 cookies and the bottle of milk costs 11 dollars, and 3 cookies and 4 bottles of milk cost 24 dollars.
Part 2. 
y=11-2x
3x+4(11-2x)=24
3x+44-8x=24
-5x=-20
x=4
y=11-8
y=3
Therefore, each cookie costs 4 dollars, and a bottle of milk costs 3 dollars.
Hope this answer helps. Let me know if you need more help next time.
<span>
</span>
7 0
3 years ago
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