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Zolol [24]
3 years ago
9

What is the value of x in the equation 25x^2=16? A.+ 5/4 B.+4 C.+ 4/5 D.+16/25

Mathematics
1 answer:
4vir4ik [10]3 years ago
5 0

Answer:

x = ± 4/5

Step-by-step explanation:

25 x^2 = 16

Divide each side by 25

25 x^2 /25 = 16 /25

x^2 = 16 /25

Take the square root of each side

sqrt(x^2) = ±sqrt(16/25)

We know that sqrt(a/b) = sqrt(a)/ sqrt(b)

x = ±sqrt(16) / sqrt(25)

x = ± 4/5

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find x. assume that segments that appear tangent are tangent. please help need answer and how to do it.
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Triangle ABC is a right triangle, meaning we can use the Pythagorean Theorem to find x.
The formula for the Pythagorean Theorem is:
a =  \sqrt{ {b}^{2}  +  {c}^{2} }
where a is the hypotenuse, and b and c are the legs.
In this problem, we have the vertical leg as 16, the horizontal leg as x, and the hypotenuse as 20. Therefore, we can say that
a = 20 \\ b = 16 \\ c = x
Therefore, we can plug into the formula to find x:a =  \sqrt{ {b}^{2}  +  {x}^{2} }  \\  {a}^{2}  =  { \sqrt{ {b}^{2}  +  {x}^{2} } }^{2}  \\  {a}^{2}  =  {b}^{2}  +  {x}^{2}  \\  {a}^{2}  -  {b}^{2}  =  {x}^{2}
We first change the variable c to x and square both sides of the equation. Then we subtract b^2 from both sides.
{x}^{2}  =  {a}^{2}  -  {b}^{2}  \\  \sqrt{ {x}^{2} }  =  \sqrt{ {a}^{2}  -  {b}^{2} }  \\ x =  \sqrt{ {a}^{2} -  {b}^{2}  }
We square root each side to find the variable answer for x. Then we plug in the numbers:x =  \sqrt{ {(20)}^{2} -  {(16)}^{2}  }  \\ x =  \sqrt{400 - 256}  \\ x =  \sqrt{144}  \\ x = 12
We find that x = 12. The answer is A. 12.
3 0
3 years ago
1+1 what does that equal
lutik1710 [3]
1+1=2
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i did the test ty hope it helps and give brainly and a thanks and 5star please :D you and you will get a A on that test or homework. IT really works

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