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IRINA_888 [86]
3 years ago
13

What two things balance to maintain the shape of a star?

Mathematics
2 answers:
viktelen [127]3 years ago
8 0

Answer: Pressure and gravity

The stars are formed by the dust and accumulation of gases present in the space. It typically formed by the fusion of the gases such as hydrogen, helium in the space. The pressure of the inner core of the star and the pressure exerted by the gases present outside the star influence the shape of the star.  The celestial bodies of the universe like stars, planets and others are acted upon by the gravitational attraction. This is responsible for keeping all the gaseous molecules present in the star in shape.

mrs_skeptik [129]3 years ago
4 0
- Pressure
- Gravity

hope this helps :D
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10 x f(7) +9 x g(-1)=
netineya [11]

the answer is 78

Step-by-step explanation:

10×7+9x-1=78

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2 years ago
What value of x makes the equation -4x – (-3 − 5x) = -3(2x − 8) true?
mezya [45]

Answer:hrhdhf end b

Step-by-step explanation:

Rndjdbajrcb

5 0
3 years ago
20 points One diagonal of a rhombus has endpoints (-10, 1) and (2, 9).
Makovka662 [10]

Check the picture below.

so as you already know, a rhombus is a parallelogram whose sides are equal, so the distance from say (-10, 1) to either endpoint of the other diagonal must be the same.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-10}~,~\stackrel{y_1}{1})\qquad \underline{(\stackrel{x_2}{-2}~,~\stackrel{y_2}{2})}\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[-2-(-10)]^2+[2-1]^2}\implies d=\sqrt{(-2+10)^2+(2-1)^2} \\\\\\ d=\sqrt{64+1}\implies \boxed{d=\sqrt{65}} \\\\[-0.35em] ~\dotfill

\bf (\stackrel{x_1}{-10}~,~\stackrel{y_1}{1})\qquad \underline{(\stackrel{x_2}{-6}~,~\stackrel{y_2}{8})}\qquad \qquad d=\sqrt{[-6-(-10)]^2+[8-1]^2} \\\\\\ d=\sqrt{(-6+10)^2+(8-1)^2}\implies d=\sqrt{16+49}\implies \boxed{d=\sqrt{65}}

4 0
3 years ago
Tan(x)sin(x)+cos(x)=sec(x)
Westkost [7]

Answer:

Step-by-step explanation:

5 0
3 years ago
What is the length of BC?
artcher [175]

Using the triangle midsegment theorem, x = 5; BC = 10 units.

<h3>What is the Triangle Midsegment Theorem?</h3>

According to the triangle midsegment theorem, ED = 1/2(BA).

Given the following:

ED = x + 2

BA = 4x - 6

x + 2 = 1/2(4x - 6)

2(x + 2) = 4x - 6

2x + 4 = 4x - 6

2x - 4x = -4 - 6

-2x = -10

x = 5

BC = 2(BE)

BC = 2(x)

BC = 2(5)

BC = 10 units

Learn more about the triangle midsegment theorem on:

brainly.com/question/12234706

#SPJ1

6 0
2 years ago
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