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4 years ago

50 POINTS

Mathematics

1 answer:

mamaluj [8]4 years ago

3 0

Answer:

The answer is below

Step-by-step explanation:

The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds: A linear model with ordered pairs at 0, 60 and 2, 75 and 4, 75 and 6, 40 and 8, 20 and 10, 0 and 12, 0 and 14, 0. The x axis is labeled Time in seconds, and the y axis is labeled Height in feet. Part A: During what interval(s) of the domain is the water balloon's height increasing? (2 points) Part B: During what interval(s) of the domain is the water balloon's height staying the same? (2 points) Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest? Use complete sentences to support your answer. (3 points) Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds.

Answer:

Part A:

Between 0 and 2 seconds, the height of the balloon increases from 60 feet to 75 feet at a rate of 7.5 ft/s

Part B:

Between 2 and 4 seconds, the height stays constant at 75 feet.

Part C:

Between 4 and 6 seconds, the height of the balloon decreases from 75 feet to 40 feet at a rate of -17.5 ft/s

Between 6 and 8 seconds, the height of the balloon decreases from 40 feet to 20 feet at a rate of -10 ft/s

Between 8 and 10 seconds, the height of the balloon decreases from 20 feet to 0 feet at a rate of -10 ft/s

Hence it fastest decreasing rate is -17.5 ft/s which is between 4 to 6 seconds.

Part D:

From 10 seconds, the balloon is at the ground (0 feet), it continues to remain at 0 feet even at 16 seconds.

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A landscaper needs 348 pounds of plant food. He has 114 pounds in his truck, and another 46 pound at his shop.

Black_prince [1.1K]

Answer:

$\frac{19}{12}\ pounds$

$1\frac{7}{12}\ pounds$

Step-by-step explanation:

<u><em>The correct question is </em></u>

A landscaper needs 3 4/8 pounds of plant food. He has 1 1/4 pounds in his truck, and another 4/6 pound at his shop. How many more pounds of plant food does the landscaper need?

Let

x ----> the additional pounds of plant food needed for the landscaper

we know that

The additional pounds of plant food needed for the landscaper plus the pounds in his truck plus the pounds in his shop must be equal to the total pounds of plant food needed

The linear equation that represent this problem is

$x+1\frac{1}{4}+\frac{4}{6}=3\frac{4}{8}$

Convert mixed number to an improper fractions

$1\frac{1}{4}=1+\frac{1}{4}=\frac{4*1+1}{4}=\frac{5}{4}$

$3\frac{4}{8}=3+\frac{4}{8}=\frac{3*8+4}{8}=\frac{28}{8}=\frac{14}{4}$

Substitute in the expression above

$x+\frac{5}{4}+\frac{4}{6}=\frac{14}{4}$

solve for x

Multiply by (4*6) both sides to remove the fractions

$24x+30+16=84$

Combine like terms left side

$24x+46=84$

subtract 46 both sides

$24x=84-46$

$24x=38$

Divide by 24 both sides

$x=\frac{38}{24}\ pounds$

simplify

$x=\frac{19}{12}\ pounds$

Convert to mixed number

$\frac{19}{12}\ pounds=\frac{12}{12}+\frac{7}{12}=1\frac{7}{12}\ pounds$

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