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sergiy2304 [10]

3 years ago

14

Help me on #8 on a-d please

1 answer:

Svet_ta [14]3 years ago

6 0

A.) -13
b.) 17
c.) 80
d.) 1
All your doing is substituting x for the number in the parenthesis and matching it with the correct function. For example, f(-3) would be 2(-3)-7 which is equal to -6-7 which is -13.

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To convert 70 minutes to seconds, you would use the ratio a. true b. false

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As a salesperson, you are paid $50 per week plus $2 per sale. This week you

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3 years ago

Read 2 more answers

What is the equation of the quadratic graph with a focus of (6, 0) and a directrix of y = −10 ?

Mademuasel [1]

Answer:

$(x-6)^{2}=20(y+5)^{2}$

Step-by-step explanation:

The standard for for the equation of a parabola is $(x-h)^{2}=4p(y-k)$

The focus is given as $(h, k+p)$

The directrix is given by $y=k-p$

Comparing focus given as $(6,0)$ to formula of focus $(h,k+p)$ , we see that $h=6$ and $k+p=0$
Comparing directrix given as $y=-10$ to formula of directrix $y=k-p$ , we can write $k-p=-10$

We can use the two system of equations [ $k+p=0$ and $k-p=-10$ ] to solve for $k$ and $p$ .

<em>Adding the two equations gives us:</em>

$2k=-10\\k=\frac{-10}{2}\\k=-5$

<em>Using this value of $k$ , we can find $p$ by plugging this value in either equation. Let's put it in </em><em>Equation 1</em><em>. We have:</em>

$k-p=-10\\-5-p=-10\\-5+10=p\\p=5$

Now, that we know $h=6$ , $k=-5$ , and $p=5$ , we can plug these values in the standard form equation to figure out the parabola's equation. Doing so and rearranging gives us:

$(x-6)^{2}=4(5)(y-(-5))^{2}\\(x-6)^{2}=20(y+5)^{2}\\$

This is the equation of the parabola with focus $(6,0)$ and directrix $y=-10$

3 0

3 years ago

Read 2 more answers