Answer:

Step-by-step explanation:
Solving trigonometric equations.
We are given a condition and we must find all angles who meet it in the provided interval. Our equation is

Solving for 5x:


The values for x will be


To find all the solutions, we'll give n values of 0, 1, 2,... until x stops belonging to the interval 
For n=0


For n=1


For n=2


For n=3


For n=4


For n=5 we would find values such as


which don't lie in the interval 
The whole set of results is

Answer:
Step-by-step explanation:
A)
Dilation. Since it's only the size of the figure that's changing
B)
Height of the smaller one: 4
Width of the smaller one: 6
Height of the bigger one: 6
Width of the bigger one: 9
6/4 = 1.5
9/6 = 1.5
Since both 6/4 and 9/6 was 1.5, that means that the Width and Height was proportional and that the two trapezoids is at a ratio o:
1 : 1.5
One unit of the smaller one is 1.5 units on the bigger one.
Answer:
-20 units??
Step-by-step explanation:
Step-by-step explanation:
Vicky Bought:
Strawberries $3.50
Carrots $2.25
Flowers $9.95
Subtotal $3.50 + $2.25 + $9.95
= $15.70
5% Sales Tax (5% of Subtotal) = 5/100 x $15.70
= $0.785 (will not round off here as it is not the final answer.)
Total = Subtotal + 5% Sales Tax
= $15.70 + $0.785
= $16.485
= $16.49 (rounded off to nearest cent)
<em>The other no. is:</em>
<u><em>32</em></u>
<em>As you can see that in the ratio given, </em><em>3</em><em> is the smaller no. and </em><em>12</em><em> too.</em>
<em>So when we divide </em><em>12 </em><em>by </em><em>3</em><em>, we get </em><u><em>4 </em></u>
<em>Then to find the other no. we need to multiply </em><em>4</em><em> with </em><em>8</em><em> (which is the other no. in the ratio given)</em>
<em>Therefore, we get the other no. as </em><u><em>32</em></u>
<em>And also when you divide </em><em>12</em><em> by </em><em>32</em><em>, </em>
<em>You get the answer as </em><u><em>3</em></u><u><em> by </em></u><u><em>8</em></u><em> </em><em>(which is the given ratio) </em>
<em />
<em>Hope you found this helpful!</em>
<em>THANK YOU!!</em>
<em>∝</em><em> Sidhdi</em>