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OleMash [197]
3 years ago
14

Help me solve this equation please. y/9 + 5 = 0

Mathematics
2 answers:
Tresset [83]3 years ago
8 0

y/9 +5 =0

 subtract 5 from each side

y/9 = -5

 multiply both sides by 9

y = -5 * 9

y = -45

ira [324]3 years ago
7 0
Multiply all 3 terms by 9 to remove the fraction 1/9:

y + 45 = 0.  Then y = -45.
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*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

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(24)

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Read 2 more answers
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