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Morgarella [4.7K]

3 years ago

15

Maria deposited some money in to an account, and had an annual simple interest rate of 5%. If she left the money in the account

for 9 months and earned $18.75 in interest, how much money did she originally deposit into the account?

1 answer:

trapecia [35]3 years ago

5 0

Answer:

$18.71

Step-by-step explanation:

18.75 = P x .05 x .75

18.75 = P x .0375

18.75 - .0375 = P

$18.71 = P

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Danny earns a monthly allowance of twenty dollars and extra seventy five cents every time he is nice to his mom. Avery earns a m

Lerok [7]

Answer:

Danny: y-=.75x+20

Avery: y=1.25x+18

Step-by-step explanation:

To write a system of equations, it usually equals y=mx+b. Since Danny and Avery both earn the set monthly allowance of 20 and 18 dollars respectively, those numbers go on the variable b since it's a set amount and they start off with that amount of money if they weren't nice to their mom at all.

Since we are trying to find the overall amount of money, let y=total money a child earns every month and x=how many times the child is nice to their mother.

The extra .75 cents Danny earns go under the variable m because it is dependent on how many times he is nice to his mom. Along with Avery.

4 0

3 years ago

Help me asap! I will give you marks

Law Incorporation [45]

Recall the binomial theorem.

$(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k$

1. The binomial expansion of $\left(1+\frac x3\right)^7$ is

$\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}$

Observe that

$k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x$

$k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2$

When we multiply these by $8-9x$ ,

• $8$ and $\frac73 x^2$ combine to make $\frac{56}3 x^2$

• $-9x$ and $\frac73 x$ combine to make $-\frac{63}3 x^2 = -21x^2$

and the sum of these terms is

$\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}$

2. The binomial expansion is

$\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k$

We get the $a^6b^2$ term when $k=2$ :

$k=2 \implies \dbinom 82 2^{8-2\cdot2} a^{8-2} b^2 = 28 \cdot2^4 a^6 b^2 = \boxed{448} \, a^6b^2$

6 0

1 year ago

In 1980, the median age of the U.S. population was 30.0; in 2000, the median age was 35.3.

miss Akunina [59]

Answer:

y = 0.265x - 494.7

Step-by-step explanation:

Let median age be represent by 'a' and time be represent by 't'

In 1980, median age is given 30

which means that

a₁ = 30

t₁ = 1980

In 2000, the median age is given 35.3

which means that.

a₂ = 35.3

t₂ = 2000

The slope 'm' of the linear equation can be found by:

m = (a₂ - a₁) /(t₂ - t₁)

m = (35.3 - 30)/(2000-1980)

m = 0.265

General form of linear equation is given by:

y = mx + c

y = 0.265x +c

Substitute point (1980,30) in the equation.

30 = 0.265(1980) + c

c = -494.7

Hence the the linear equation can be written as:

y = mx + c

y = 0.265x - 494.7

4 0

3 years ago

A triangle T is bounded (on three sides) by the lines x = 6, y = 0, and y = 3 2 x. A rectangle of width w is inscribed inside T.

Viktor [21]

Answer:

33.85 units^2

Step-by-step explanation:

you must first draw the triangle on the plane using the equations (see

attached file), you will have a right angle triangle with a height of 192 and a base of 6.

then you calculate the angle with the tangent function = 88.21

Then you use the small triangle to find the value of a (see attached file).

Finally, you propose an equation for X to find one of the sides of the triangle, once you have x squared it, and you already have the area,

i attached procedure

7 0

3 years ago

Type the correct answer in each box. Use numerals instead of words.

sweet [91]

Answer: -(x + 3)^2 = 3

Explanation:

-x^2 - 6x + 6 = 0
-x^2 - 6x = -6
-x^2 - 6x + 9 = -6 + 9
-(x + 3)^2 = 3

6 0

3 years ago

Read 2 more answers