Answer:
7x−3=7k,x=7k+3,k∈ℤ
Step-by-step explanation:
3x ≡ 2 (mod 7)
3 is a solution, since 3×3−2=7.
All solutions are 3+7ℤ
y=3x−2/7=3(x−3)+7/7=3(x−3)/7+1
7x−3=7k,x=7k+3,k∈ℤ
Answer: f(x) is just a fancy way of writing y in an equation
Step-by-step explanation:
Example: f(x)= 2x+4 is the same as y= 2x+4
The required Comparison of the inequalities are
- The |x – 1| + 1 > 15 represents the value of x lies between 13<x<15.
The range of values encompassing the region's junction is (-13, 15).
- If x is more than or equal to 15, then x-11+1>15 indicates the value of x is greater than or equal to 13. None of the regions in the intersection are empty.
<h3>What is inequality?</h3>
When comparing two numbers, an inequality indicates whether one is less than, larger than, or not equal to the other.
We take into account the various variables of the inequality
|x – 1| + 1 > 15
Therefore
|-x-1|+1-1<15-1
|-x-1|-1 <14
13<x<15
The required region lies between the inequality -13 <x< 15.
Simplify the inequality Ix-11+1 > 15 we get,
|x-1|+1 > 15
|x+1| +1-1 >15-1
|x-1| > 14
x> 15
x<-13
- If x has a value between -13 and x + 15, then the expression "|x-1|+1+115" is true. The range "(-13, 15)" contains the intersection of the region.
- If "|x-1|+1>15" then either "x >15" or "x-13" applies to the value of x. This region's intersection is unoccupied.
Read more about inequalities
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Answer:138
Step-by-step explanation:
First plug in the c and d values into the expression:
6(5)^2-5(4)+8
Remember PEMDAS, so you do 5^2 first getting you 25.
6(25)-5(4)+8
Continue with PEMDAS and multiply -5 and 4, and that gets you -20.
150-20+8
Now you simplify the expression to get: 138.
This problem can be solved using two equations:
The first represents the total trip, which is the miles driven in the morning added to those in the afternoon. Let's call the hours driven in the morning X and the hours driven in the afternoon Y. We get: X + Y = 248.
The second equation relates the miles driven in the morning compared to the afternoon. Since 70 fewer miles were driven in the morning than the afternoon, then X = Y - 70.
Now substitute the equation for morning hours (equation 2) into the total miles equation (equation 1). We get:
(Y - 70) + Y = 248
2Y - 70 = 248
2Y = 318
Y = 159
We know that Winston drove 159 miles in the afternoon.
To find the morning hours, just substitute 159 into the equation for morning hours (equation 2)
X = 159 - 70
X = 89
We now know that Winston drove 89 miles in the morning.
We can check our work by plugging both distances into the total distance equation: 89 + 159 = 248
