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3 years ago

Solve the compound inequality 8x > –32 or 6x ≤ –48.

Mathematics

2 answers:

Reil [10]3 years ago

8 0

Answer:

(-∞,-8] U (-4,∞)

Step-by-step explanation:

$8x > -32 \ or \ 6x\leq-48$

To solve the compound inequality we solve each inequality and combine the solutions

$8x > -32$

Divide both sides by 8

$x>-4$

$6x\leq-48$

Divide both sides by 6 to get x alone

$x\leq-8$

Now we combine both inequalities

$x>-4$ or $x\leq-8$

WE combine both inequalities

(-∞,-8] U (-4,∞)

34kurt3 years ago

6 0

On the <span>8x > –32 first divide by the 8 from the both sides.

8x/8 as a fractions and it is greater than negative 32/8 as a fraction. And the equals to x is greater than negative 4.

On the </span>6x ≤ –48. Then divide by 6 from the both sides.

6x/6 as a fractions and it is less than negative 48/6 as a fraction. And the equals to x≤ negative 8.

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