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e-lub [12.9K]
3 years ago
9

A restaurant offers a dinner special in which diners can choose anyone of three appetizers, anyone of four entries, anyone of fi

ve side dishes, and anyone of six desserts. How many different meals are possible?
Mathematics
1 answer:
Ainat [17]3 years ago
3 0

Answer:

4 meals , is this the ans

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nadya68 [22]
N=27
D=80

Explaintion:
20 n in a dollar
10 d in a dollar
So 27=1.35$
27*3=81-1=80=8.00$+1.35$=9.35$
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Solve the right triangle, ΔABC, for the missing sides and angle to the nearest tenth given angle B = 39° and side c = 13.
hram777 [196]

Answer:

Part 1) b=8.2\ units

Part 2) a=10.1\ units

Part 3) A=51\° and C=90\°

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

Find the side b

we know that

In the right triangle ABC

The function sine of angle B is equal to divide the opposite side angle B (AC) by the hypotenuse (AB)

sin(B)=AC/AB

we have

AB=c=13\ units

AC=b

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substitute

sin(39\°)=b/13

solve for b

b=(13)sin(39\°)

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step 2

Find the side a

we know that

In the right triangle ABC

The function cosine of angle B is equal to divide the adjacent side angle B (BC) by the hypotenuse (AB)

cos(B)=BC/AB

we have

AB=c=13\ units

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cos(39\°)=a/13

solve for a

a=(13)cos(39\°)

a=10.1\ units

step 3

Find the measure of angle A

we know that

In the right triangle ABC

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B=39\°

∠A+∠B=90° ------> by complementary angles

substitute the given value

A+39\°=90\°

A=90\°-39\°

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