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Mathematics

2 answers:

a_sh-v [17]3 years ago

7 0

Expand the bracket firsr by multiplying everything in the bracket by - 5 and you now have 3-10x-5<10, which simplifies to -2-10x<10
Bring - 2 over to the other side by adding 2 on both sides and now you have -10x<12. Now simply divide both sides by -10 to isolate x and you get x<-1.2, or x<-6/5 as a fraction

yaroslaw [1]3 years ago

3 0

3 - 5(2x + 1) ≤ 10
3 - 10x - 5 ≤ 10
-10x - 2 ≤ 10
+2 +2
___________
-10x ≤ 12
Divide -10 on both sides.
x ≤ 12/-10
x ≤ -1.2
-1.2 into a fraction is -6/5.
x ≤ -1.2 or x ≤ -6/5

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Read 2 more answers

Can someone help me with this

SashulF [63]

Answer:

$\angle NRQ =85 \degree$

Given:

$\angle RPQ = 45 \degree \\ \angle PQR = (6x + 4)\degree \\ \angle NRQ = (15x - 5)\degree$

Step-by-step explanation:

Property used: An exterior angle of a triangle is equal to the sum of the opposite interior angles.

$= > \angle RPQ + \angle PQR = \angle NRQ \\ \\ = > 45 \degree + (6x + 4)\degree = (15x - 5)\degree \\ \\ = > 45\degree + 6x\degree + 4\degree = 15x\degree - 5\degree \\ \\ = > 49\degree + 5 \degree= 15x\degree - 6x\degree \\ \\ = > 54\degree = 9x\degree \\ \\ = > 9x\degree = 54\degree \\ \\ = > x\degree = (\frac{54}{9} )\degree \\ \\ = > x\degree = 6\degree \\ \\ Putting \: value \: of \: x \: in \: \angle NRQ \\ \\ = > \angle NRQ = (15x - 5)\degree \\ \\ = > \angle NRQ = (15 \times 6 - 5) \degree \\ \\ = > \angle NRQ =85 \degree$

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3 years ago