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3 years ago

6

Ann is buying a house that costs $250,000. She is making a down payment of 15 percent, and her closing costs will amount to 3 pe

rcent. Over the life of her loan, she will pay $282,089.89 in monthly payments. What is the total cost of her house?

1 answer:

Ad libitum [116K]3 years ago

8 0

Down payment = 15% of $250,000 = 0.15 x 250000 = 37,500
closing costs = 3% of $250,000 = 0.03 x 250000 = 7,500
Monthly payments = $282,089.89

Total cost of the house is 37,500 + 7,500 + 282,089.89 = $327,089.89

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I need to figure out how many solutions does the system of equations below have.

Aleonysh [2.5K]

Answer:

The system has one solution.

Step-by-step explanation:

To find the number of solutions of the system, we equal both equations for y.

If we have ax = b, in which both a and b are different of 0, we have one solution.

If both a and b are 0, we have infinite solutions.

If a is 0 and b is not, there are no solutions.

y=6/7x-8 and y=7/9x+10/9

So

$\frac{6x}{7} - 8 = \frac{7x}{9} + \frac{10}{9}$

$\frac{6x}{7} - \frac{7x}{9} = \frac{10}{9} + 8$

$\frac{54x - 49x}{63} = \frac{10}{9} + \frac{72}{9}$

$\frac{5x}{63} = \frac{82}{9}$

$45x = 63*82$

Both a and b are different of 0, so the system has one solution.

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2 years ago

9. Find P(rolling 1 or 5) with one number cube.

marta [7]

Answer:

1/3

Step-by-step explanation:

There are 6 possible outcomes when rolling 1 die

1,2,3,4,5,6

P ( 1 or 5) = number of times 1 or 5 happens / total outcomes

= 2/ 6

= 1/3

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3 years ago

Determine the intercepts of the line. -5x+9y=-18

Stolb23 [73]

Answer:

x-intercept = (18/5,0)

y-intercept = (0,-2)

Step-by-step explanation:

I graphed it and found the intercepts

brainliest would be great

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2 years ago

It is known that the life of a particular auto transmission follows a normal distribution with mean 72,000 miles and standard de

scoray [572]

Answer:

a) $P(X$

$P(z$

b) $P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)$

$P(z>-0.583)=1-P(Z$

c) $P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)$

$P(z>2.33)=1-P(Z$

Sicne this probability just represent 1% of the data we can consider this value as unusual.

d) $z=1.28$

And if we solve for a we got

$a=72000 +1.28*12000=87360$

So the value of height that separates the bottom 90% of data from the top 10% is 87360.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the life of a particular auto transmission of a population, and for this case we know the distribution for X is given by:

$X \sim N(72000,12000)$

Where $\mu=72000$ and $\sigma=12000$

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And we can find this probability using excel or the normal standard table and we got:

$P(z$

Part b

$P(X>65000)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)$

And we can find this probability using the complement rule and excel or the normal standard table and we got:

$P(z>-0.583)=1-P(Z$

Part c

$P(X>100000)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)$

And we can find this probability using the complement rule and excel or the normal standard table and we got:

$P(z>2.33)=1-P(Z$

Sicne this probability just represent 1% of the data we can consider this value as unusual.

Part d

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.1$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=1.28$

And if we solve for a we got

$a=72000 +1.28*12000=87360$

So the value of height that separates the bottom 90% of data from the top 10% is 87360.

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3 years ago

How many times can 10 go into 44

Nitella [24]

4 times because if you count 10, 20, 30, 40, so it has to be 4

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2 years ago

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