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3 years ago

A box contains 16 cherry fruit chews, 15 peach fruit chews, and 12 Plumford choose. Which two flavors are in the ratio 5 to 4?

1 answer:

5 0

A couple of different ways to solve this.

Build ratio 5/4
Multiply by 2/2 to get equivalent, which is 10/8 - this does not match any possible solution.
Now do 5/4 * 3/3 to get 15/12. This works, so the answer is 15 peach fruit chews/12 plumb fruit chews.

Trial and error method.

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True or False: A race car driver tested his car for time from 0 to 60 mph, and in 20 tests obtained an average of 4.85 seconds w

vredina [299]

Answer:

False

Step-by-step explanation:

given that a race car driver tested his car for time from 0 to 60 mph, and in 20 tests obtained an average of 4.85 seconds with a standard deviation of 1.47 seconds.

Sample size n = 20

since population standard deviation is not known, we can use t critical value for finding out the confidence interval

df=19

t critical = 2.045

Margin of error = $2.045*\frac{s}{\sqrt{n} } \\=2.045*\frac{1.47}{\sqrt{20} } \\=0.6722$

conidence interval = Mean±Margin of error

= $(4.85-0.6722, 4.85+0.6722)\\= (4.1778, 5.5222)$

The given confidence interval is (4.52, 5.18)

Hence the statement is false.

5 0

4 years ago

WILL MARK BRAINLIEST

miv72 [106K]

Answer:

1) 4+n<13

2) 11-n>17

3) n-8≥9 or n+(-8)≥9

4) 16<8n

5) n·5≤30

Step-by-step explanation:

3 0

3 years ago

Denise is a professional swimmer who trains, in part, by running. she would like to estimate the average number of miles she run

SSSSS [86.1K]

Given:
n = 20, sample size
xbar = 17.5, sample mean
s = 3.8, sample standard deiation
99% confidence interval

The degrees of freedom is
df = n-1 = 19

We do not know the population standard deviation, so we should determine t* that corresponds to df = 19.
From a one-tailed distribution, 99% CI means using a p-value of 0.005.
Obtain
t* = 2.8609.

The 99% confidence interval is
xbar +/- t*(s/√n)

t*(s/√n) = 2.8609*(3.8/√20) = 2.4309
The 99% confidence interval is
(17.5 - 2.4309, 17.5 + 2.4309) = (15.069, 19.931)

Answer: The 99% confidence interval is (15.07, 19.93)

4 0

3 years ago

3. A piece of white oak has a densityof 0.77 g/cm and a mass of 100 g,what would be the volume of thesample? PLEASE HELP!

Nezavi [6.7K]

$\text{Volume}=129.87cm^3$

Explanation

Step 1

the density of an object is given by:

$\text{density}=\text{ }\frac{mass}{\text{volume}}$

Step 2

let

$\begin{gathered} \text{density}=0.77\frac{g}{cm^3} \\ \text{mass}=\text{ 100 g} \\ \end{gathered}$

Step 3

replace,

$\begin{gathered} \text{density}=\text{ }\frac{mass}{\text{volume}} \\ 0.77\frac{g}{cm^3}=\frac{100g}{\text{volume}} \\ \text{volume}\cdot0.77\frac{g}{cm^3}=\text{1}00\text{ g} \\ \\ \text{Volume}=\frac{100\text{ g}}{0.77\frac{g}{cm^3}} \\ \text{Volume}=129.87cm^3 \end{gathered}$

I hope this helps you

5 0

1 year ago

PLEASE HELP I GIVE THANKS

Art [367]

4x-10=18

4x=18+10

4x=28

x=28/4
<span>
x=7</span>

6 0

3 years ago