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3 years ago

Kim described two subatomic particles below:

Chemistry

1 answer:

raketka [301]3 years ago

3 0

<h2>Answer:Particle P attracts particle Q.</h2>

Explanation:

Given that $P$ has least mass.

Since electron has a negligible mass, $P$ can be taken as electron.

Given that $Q$ is more massive with a charge.

Since proton is more massive than electron and is also charged,

we can take $Q$ as proton.

Since proton is positively charged and electron is negatively charged,both of them attract each other.

So,particle $P$ attracts particle $Q$ .

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3 years ago

How many moles are in 6.21x1025 atoms of magnesium oxide?

Rasek [7]

Answer: 55.56 moles of MgO

Explanation:

1 mole = avogadro number

if 6.21x10^25 atoms then molecules of MgO (equal numbers of Mg and O atoms)

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5 0

3 years ago

Cuando se trata Ca3P2 con agua, los productos son Ca(OH)2 y PH3. Calcular el peso máximo obtenido al reaccionar 2 g de Ca3P2 con

anyanavicka [17]

Answer:

0.629 gramos de PH3 es la máxima de cantidad que puede ser producida.

Explanation:

¡Hola!

En este caso, dado que tenemos la siguiente reacción química, la cual se puede balancear directamente:

$Ca_3P_2+6H_2O\rightarrow 3Ca(OH)_2+2PH_3$

Podemos calcular la masa máxima de cualquier producto, digamos PH3, al comparar la masa de este, que 2 g the Ca3P2 y 1 g de H2O producen por separado y de acuerdo a la estequiometría:

$2gCa_3P_2 *\frac{1molCa_3P_2 }{182.18gCa_3P_2 }*\frac{2molPH_3}{1molCa_3P_2 } *\frac{34gPH_3}{1molPH_3 } =0.747gPH_3\\\\1gH_2O *\frac{1molH_2O }{18.02gH_2O}*\frac{2molPH_3}{6molH_2O} *\frac{34gPH_3}{1molPH_3 } =0.629gPH_3$

De este modo, infermos que solamente 0.629 gramos the PH3 pueden ser obtenidos al ser el agua el reactivo límite.

¡Saludos!

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3 years ago