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3 years ago

Kim described two subatomic particles below:

Chemistry

1 answer:

raketka [301]3 years ago

3 0

<h2>Answer:Particle P attracts particle Q.</h2>

Explanation:

Given that $P$ has least mass.

Since electron has a negligible mass, $P$ can be taken as electron.

Given that $Q$ is more massive with a charge.

Since proton is more massive than electron and is also charged,

we can take $Q$ as proton.

Since proton is positively charged and electron is negatively charged,both of them attract each other.

So,particle $P$ attracts particle $Q$ .

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What is the molar mass of H2SO4

Zigmanuir [339]

98.09 grams per mole rounded off to two decimal places

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3 years ago

The system co2(g) + h2(g) ⇀↽ h2o(g) + co(g) is at equilibrium at some temperature. at equilibrium a 4.00 l vessel contains 1.00

Marina CMI [18]

<u>Answer:</u> The moles of $CO_2$ added to the system is 7.13 moles

<u>Explanation:</u>

We are given:

Moles of $CO_2$ at equilibrium = 1.00 moles

Moles of $H_2$ at equilibrium = 1.00 moles

Moles of $H_2O$ at equilibrium = 2.40 moles

Moles of $CO$ at equilibrium = 2.40 moles

Volume of the container = 4.00 L

Concentration is written as:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume (in L)}}$

The given chemical equation follows:

$CO_2(g)+H_2(g)\rightleftharpoons H_2O(g)+CO(g)$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[CO][H_2O]}{[CO_2][H_2]}$

Putting values in above equation, we get:

$K_c=\frac{(\frac{2.40}{4.00})\times (\frac{2.40}{4.00})}{(\frac{1.00}{4.00})\times (\frac{1.00}{4.00})}\\\\K_c=5.76$

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of CO = 0.791 mol/L

Volume of solution = 4.00 L

Putting values in above equation, we get:

$0.791M=\frac{\text{Moles of CO}}{4.00L}\\\\\text{Moles of CO}=(0.791mol/\times 4.00L)=3.164mol$

Extra moles of CO = (3.164 - 2.40) = 0.764 moles

Let the moles of $CO_2$ needed be 'x' moles.

Now, equilibrium gets re-established:

$CO_2(g)+H_2(g)\rightleftharpoons H_2O(g)+CO(g)$

Initial: 1.00 1.00 2.40 2.40

At eqllm: (0.236+x) 0.236 3.164 3.164

Again, putting the values in the expression of $K_c$ , we get:

$5.76=\frac{(\frac{3.164}{4.00})\times (\frac{3.164}{4.00})}{(\frac{0.236+x}{4.00})\times (\frac{0.236}{4.00})}\\\\5.76=\frac{10.011}{0.056+0.236x}\\\\x=7.13$

Hence, the moles of $CO_2$ added to the system is 7.13 moles

4 0

3 years ago

PLEASE HELP! 80 points!!

ludmilkaskok [199]

Answer:

the metal is gold I'd say

8 0

3 years ago

Use condensed electron configurations and Lewis electron-dot symbols to depict the ions formed from each of the following atoms,

enot [183]

Condensed electron configuration of :

Ga = [Ar] 3d¹⁰ 4s² 4p¹.

O = 1s² 2s² 2p⁴

Gallium belongs to group 13 of the periodic table with 3 valence electrons. Oxygen (Atomic number = 8 and electronic configuration = 2,6) belongs to group 16 of the periodic table with 6 valence electrons. To achieve the octet stability criteria 2 gallium atoms will donate their 3 electrons each to 3 oxygen atoms.

The 3 oxygen atoms due to their high electron attracting ability will accept those electrons resulting in Ga3+ cation and O₂⁻ anion.

Thus, the formula of their compound if Ga₂O₃.

To know more about Electron configuration, refer to this link:

brainly.com/question/11530251

#SPJ4

6 0

1 year ago

What does a solute do in a solution

valentinak56 [21]

A solute is a substance that dissolves into another substance , and forms a solution.

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4 years ago