Convert both to mixed numbers:
16/3 = 5 1/3
-9/2 = -4 1/2
Which integers are between -4 1/2 and 5 1/3?
The solution set is -4, -3, -2, -1, 0, 1, 2, 3, 4, 5
I hope I helped you with your solution! If you could give me brainliest, I would be very thankful!
Answer:
Step-by-step explanation:
There are 240 boxes with 25 bags each. If each bag weighs 0.69 kg. What is the weight of coffee?
Answer:
B
Step-by-step explanation:
Answer:
7x + 33 -I could be wrong I'm not an expert in maths jus trying to help
Step-by-step explanation:
x + 13 9x-7
so first you need to times both by two because there are two of both sums
2(x+13) so you times both numbers by 2 so
= 2x+26
and do the same with 9x - 7 so
2(9x-7) = 18x - 14
and then you add them together and find the like terms.
Like terms means for example in the equation:
2x + 3x - 4 + 3
the like terms are the two numbers that are the same like 2x and 3x are the same since they are both the same term and since there is a plus sign before the 3x you add them so 5x and then you need to do -4 + 3 = 7 and so the answer is 5x + 7.
In this case its:
2x + 26 + 5x + 7. So the like terms are 2x and +5x and +26 and +7.
So 2x + 5x = 7x and 26 + 7 = 33.
So the final equation is 7x + 33
Hope this helps :D
Answer:
Step-by-step explanation:
(8x²-18x+10)/(x²+5)(x-3)
express the expression as a partial fraction:
(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +bx+c/x²+5
both denominator are equal , so require only work with the nominator
(8x²-18x+10)=(x²+5)A+(x-3)(bx+c)
8x²-18x+10= x²A+5A+bx²+cx-3bx-3c
combine like terms:
x²(A+b)+x(-3b+c)+5A-3c
(8x²-18x+10)
looking at the equation
A+b=8
-3b+c=-18
5A-3c=10
solve for A,b and c (system of equation)
A=2 , B=6, and C=0
substitute in the value of A, b and c
(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +(bx+c)/x²+5
(8x²-18x+10)/[(x^2+5)(x-3)] = 2/x-3 + (6x+0)/(x²+5)
(8x²-18x+10)/[(x^2+5)(x-3)] =
<h2>2/(x-3)+6x/x²+5</h2>
(4x+2)/[(x²+4)(x-2)]
(4x+2)/[(x²+4)(x-2)]= A/(x-2) + bx+c/(x²-2)
(4x+2)=a(x²-2)+(bx+c)(x-2)
follow the same step in the previous answer:
the answer is :
<h2>(4x+2)/[(x²+4)(x-2)]= 5/4/(x-2) + (3/2 -5x/4)/(x²+4)</h2>
