Answer:
I suppose we want to find the side length of the square.
We know that:
The area of the square is 49cm^2
The distance between one of the vertices of the square and the middle of the square is:
BE = 4.95cm
Now let's remember some things.
For a square of side length L, the area is:
A = L^2
and the diagonal length is:
D = √(2)*L
In this case, we know that half of the diagonal is equal to:
BE = 4.95 cm
Then the diagonal is:
D = 2*BE = 2*4.95cm = 9.9cm
And for the diagonal formula, we have:
D = 9.9cm = √(2)*L
Then the side length is:
L = 9.9cm/√(2) = 7cm
And if we check the area of this square, is:
A = L^2 = (7cm)^2 = 49cm^2
So it checks.
Then we can conclude that the sidelength of the square is 7cm, which means that:
AB = 7cm
BC = 7cm
CD = 7cm
DA = 7cm
The answer to the question is B. 8
- 
+ 6
divide each term on the numerator by 7b
= - 7
/ 7b + 42 / 7b
= - + 6
Answer:
Step-by-step explanation:
"length is 4 meters less than 2 times the width"
L = 2W+4
"perimeter is 40 meters"
2L+2W = 40
L+W = 20
(2W+4) + W = 20
3W + 4 = 20
W = 16/3 meters
Area of a circle=πr²
area of this cirlce=π*(12 ft)²=144π ft²≈452.39 ft².
answer 1= the area of this circle is 452.39 ft².
Perimeter of a circle=2πr.
Perimeter of this cirlce=2π(12 ft)=24π ft≈75.4 ft
<span>answer 2= the perimeter of this cirlce is 75.4 ft.</span>
