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dimulka [17.4K]
3 years ago
13

Choose what the expressions below best represent within the context of the word problem.

Mathematics
2 answers:
olganol [36]3 years ago
6 0
Let x = the ones digit
Let y = the tens digit

x+2y=12
x=2y
x+y=12 substitute x for 2y to get:
(2y)+y=12 add like terms to get:
3y=12
3y=12 divide both sides by 3 to get:
y=4
x+y=12 substitute y for 4 to get:
x+4=12 subtract 4 from both sides to get:
x=8
so if x=ones
and y=tens
<span>then the answer is 48</span>
aleksandrvk [35]3 years ago
5 0
Let's just try to solve the problem.... BA B is the tens digit A is the ones digit B = 2A A + B = 12 so by substitution for B A + 2A = 12 3A = 12 Can you solve for A ? Then solve for B and check your answer in the other equation 
I can see that the answer is 48... but let's work the problem Let the number be represented by xyy is the units digitx is the tens digit x+y=12.   the sum of the digits is 12y=2x.      the units digit is twice the tens digit replacing y with 2x in the first equation we have x+2x=123x=12x=4 y=2x =2(4)=8 xy = 48
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GaryK [48]

Hello from MrBillDoesMath!

Answer:   9

Discussion

By the Pythagorean theorem, the length of the third side (the hypotenuse) in the triangle with sides 4 and 6 is sqrt ( 4^2 + 6^2) = sqrt (52)

Applying Pythagoras to the left most triangle (sides, x and 6) gives:

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Finally, in the big right triangle (the one containing the two right triangles)

(x + 4) ^2  =   (sqrt(52)) ^2  + m^2


OK!   Subtract the first equation from the second:

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-----------------------------------------------------


( x+4)^2 - x^2 - 36 = 52 + (m^2 - m^2)  =>

x^2 + 8x + 16  - x^2 -36 = 52  =>

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0 +              8x - 20       = 52 =>

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x = 9




Thank you,

MrB

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3 years ago
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