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Vitek1552 [10]
4 years ago
9

Round the number 1258 into significant figures

Mathematics
2 answers:
aniked [119]4 years ago
6 0

Answer:

I think it's 12.58 but if you are rounding the number it would be 1.3. Not sure if that answeres you though.

Step-by-step explanation:

BartSMP [9]4 years ago
6 0

Answer:

1 sig fig = 1

2 sig fig = 13

3 sig = 126

4 sig fig 1258

Step-by-step explanation:

I think that's what you're asking but I'm not sure

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5=1/5w in algebraically
Rudik [331]

Answer:w = -5/4

Step-by-step explanation:

3 0
4 years ago
The population of mosquitoes in a certain area increases at a rate proportional to the current population, and in the absence of
Alexandra [31]

Answer:

Population of mosquitoes in the area at any time t is:

P(t) =504,943.26  -104,943.26e^{0.693t}

Step-by-step explanation:

assume population at any time t = P(t)

population increases at a rate proportional to the current population:

⇒dP/dt ∝ P

 \implies \frac{dP}{dt} =kP----(1)

where k is constant rate at which population is doubled

solving (1)

ln|P(t)|=kt +C\\P(t)= e^{kt+C}\\P(t)=Ce^{kt}

t=0\\P(0) = P_{o}\\\implies C= P_{o}\\P(t) =P_{o}e^{kt}\\ ---- (2)

initial population = 400,000

population is doubled every week

                                                 ⇒P(1)=2P(0)

Using (2)

                                 P_{o}e^{k(1)} = 2P_{o} e^{k(0)}\\

                                            e^{k} =2\\k=ln|2|\\

In presence of predators amount is decreased by 50,000 per day

Then amount decreased per week = 350,000

In this case (1) becomes

\frac{dP}{dt}=kP-350,000\\\frac{dP}{dt} - kP=-350,000\\ ---(3)

solving (3) by calculating integrating factor

                                          I.F=e^{\int-k dt}

Multiplying I.F with all terms of (3)

e^{-kt}\frac{dP}{dt} - ke^{-kt}P =-350,000 e^{-kt}\\\frac{d}{dt}(e^{-kt}P) =  -350,000 e^{-kt}

Integrating w.r.to t

                         e^{-kt}P(t)= \frac{350,000e^{-kt}}{k} +C

                         P(t) =\frac{350,000}{k} +Ce^{kt}\\

                                          k=ln|2| =0.693

                          P(t) =504,943.26 + Ce^{0.693t}\\

at t=0

                        P(0) =504,943.26 + Ce^{0.693(0)}

                        400,000 =504,943.26 + C

                           C = -104,943.26

So, population of mosquitoes in the area at any time t is

                  P(t) =504,943.26  -104,943.26e^{0.693t}

6 0
3 years ago
Solutions of x^2-2x=8
Andreyy89

Answer:

-√2

Step-by-step explanation:

  x² - 2x = 8          Apply the square root to both sides

√x² - 2x = √8        Divide both sides by -2

           x = -√2

    <u><em>Extra info:</em></u>

√8 = 2√2 = 2.828427125  

-√2 = -1.414213562

7 0
3 years ago
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slavikrds [6]

Answer:

Each shirt would cost $2.75

Step-by-step explanation:

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Can the sides of a triangle have lengths 6, 6 , 15
dimaraw [331]

Answer:

I don't think it can, because the two smaller sides cannot have a sum of less than the third side. 6+6=12, and 12 is less than 15, so it cannot be possible. You can even test this out on a piece of paper and you will see that it is not possible.

5 0
3 years ago
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