What is the length of a rectangle with an area of (4x^2-10x-6) and a width of (x-5)
1 answer:
You might be interested in
Currently the equation 6x - 2y = 18 is in standard form. Convert the standard form equation into a slope-intercept form and we can find the slope easily.
Solve for y.
6x - 2y = 18
-2y = 18 - 6x <-- Subtract 6x from each side. This is to isolate the 2y term
2y / -2 =
<-- Divide each side by 2. This it to
get rid of the 2 coefficient.
y = -9 + 3x
Rearrange the right-hand side a bit.
y = -9 + 3x becomes y = 3x - 9
Now it is in slope-intercept form.
The slope is the coefficient of the x variable.
So, 3 is the slope.
Solve for y.
6x - 2y = 18
-2y = 18 - 6x <-- Subtract 6x from each side. This is to isolate the 2y term
2y / -2 =
get rid of the 2 coefficient.
y = -9 + 3x
Rearrange the right-hand side a bit.
y = -9 + 3x becomes y = 3x - 9
Now it is in slope-intercept form.
The slope is the coefficient of the x variable.
So, 3 is the slope.
Answer:
75%
88.89%
Step-by-step explanation:
Given :
Mean = 70
Standard deviation = 12
Since the data is said to be extremely skewed, we apply Chebyshev's theorem rather than the empirical rule :
The minimum proportion of observation between 46 and 94
Chebyshev's theorem :
1 - 1 / k²
k = number of standard deviations from the mean
k = (94 - 70) / 12 = 24 / 12 = 2
Hence, we have ;
1 - 1/2²
1 - 1/4
1 - 0.25 = 0.75
Hence, The minimum proportion of observation between 46 and 94 is 75%
Between 36 and 106 :
k = (106 - 70) / 12 ;
k = 36/12 = 3
Hence,
1 - 1/3² = 1 - 1/9 = 8/9 = 0.8888 = 88.89%
The minimum proportion of observation between 34 and 106 is 88.89%
