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ella [17]
3 years ago
5

The length of a rectangular driveway is five feet more than three times the width. The area is 350ft2. Find the width and length

of the driveway.
Mathematics
1 answer:
crimeas [40]2 years ago
4 0

Answer:

  • width -- 10 ft
  • length -- 35 ft

Step-by-step explanation:

We can let x represent the width. Then the length will be represented by (3x+5), a value 5 more than 3 times the width.

The area is the product of length and width, so is ...

  A = (3x +5)(x) = 3x^2 +5x

To make the area 350, we can find the value of x from ...

  3x^2 +5x = 350

This can be solved a number of ways. One of them is "completing the square".

  3(x^2 +5/3x) = 350

We choose to divide by 3 and add the square of half the x-coefficient.

  x^2 +5/3x +(5/6)^2 = (350/3) + (5/6)^2

  (x +5/6)^2 = 4225/36 . . . . simplify

  x +5/6 = ±√(4225/36) = ±10 5/6 . . . . take the square root

  x = 10  or  -11 2/3 . . . . subtract 5/6

The positive solution is the one of interest: x = 10.

The driveway is 10 ft wide and 35 ft long.

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The weight of a bull clad is 388 kilograms. If it’s weight increases at a rate of 1 2/5 kilograms per day how long it will take
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Answer:

It will take  <u><em>80 days</em></u>  for the bull calf to reach a weight of 500 kilograms.

Step-by-step explanation:

Given:

The weight of a bull calf is 388 kilograms.

Now, to find the weight of bull calf of how long it will take to reach a weight of 500 kilograms, if it’s weight increases at a rate of 1 2/5 kilograms per day.

Required weight which to be increased = 500 - 388 = 112 kilograms.

Rate of weight increase = 1\frac{2}{5}=\frac{7}{5}

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Thus, the time required = \frac{required\ weight}{rate\ of\ weight}

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<em>The time required   =    80 days</em>.

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