Answer:
(9-x)
Step-by-step explanation:
Answer:
15 seconds
Step-by-step explanation:
If you make a table of values for the dog and the squirrel using d = rt, then the rates are easy: the dog's rate is 150 and the squirrel's is 100. The t is what we are looking for, so that's our unknown, and the distance is a bit tricky, but let's look at what we know: the dog is 200 feet behind the squirrel, so when the dog catches up to the squirrel, he has run some distance d plus the 200 feet to catch up. Since we don't know what d is, we will just call it d! Now it seems as though we have 2 unknowns which is a problem. However, if we solve both equations (the one for the dog and the one for the squirrel) for t, we can set them equal to each other. Here's the dog's equation:
d = rt
d+200 = 150t
And the squirrel's:
d = 100t
If we solve both for t and set them equal to each other we have:

Now we can cross multiply to solve for d:
150d = 100d + 20,000 and
50d = 20,000
d = 400
But we're not looking for the distance the squirrel traveled before the dog caught it, we are looking for how long it took. So sub that d value back into one of the equations we have solved for t and do the math:

That's 1/4 of a minute which is 15 seconds.
Just look at the percentages and make them into fractions. You can think about it like money. 50 cents is half of a dollar, so %50 is 1/2. for the decimals, you just take the percent and put a decimal point in front of the answer, so 28% is .28, 50% is .50, 18% is .18. For fraction to decimals, you could just put 1 divided by 4 into a calculator and it will tell you .25, which is the decimal, and 25 cents is one fourth of a dollar, so it works out.
Hope this helps! Let me know if you have any more questions!