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3 years ago

14

Boats can travel anywhere between 50 and 150 kilometers per hour. Choose a speed between 50 and 150. Convert the speed you chose

into meters per second

1 answer:

lara [203]3 years ago

3 0

Take 75 kilmoeters That is 1250 meters per second

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Can anyone help me on the last question?

Novosadov [1.4K]

Answer:

<h2> 0.7</h2>

Step-by-step explanation:

A' is everything what is not A

So:

A' = {9, 10, 11, 12, 13, 15, 16}

Number of ways it can happen: |A'| = 7

Total number of outcomes: |Ω| = 10

Probability of an event happening:

$\bold{P(A')=\dfrac{|A'|}{|\Omega|}=\dfrac7{10}=0.7}$

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3 years ago

Solve 6x(6x) + 11x - 35 = 0

Murljashka [212]

$36x^2 + 11x - 35=0\\\\ \frac{-b \pm \sqrt{ b^2 -4( a)(c)} }{2(a)}\\\\ \frac{-11\pm \sqrt{11^2 -4(36)(-35)} }{2(36)}\\ \\ \frac{-11\pm \sqrt{5161 } }{72}\\\\\\ x = 0.8450013919812116\\\\ \text{ } x = -1.1505569475367672$

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2 years ago

Read 2 more answers

Can someone please help me with this algebra question? Image attached.

horsena [70]

Answer:

2 relative maxima and minima

(2, 6.2) = maxima

(0, -4) = minima

*tell me if I got this wrong

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3 years ago

Find the sum and product of the roots.

xz_007 [3.2K]

Answer:

sum= -3 product=-4

Step-by-step explanation:

2x^2-2x+8x-8

2x(x-1)+8(x-1)

(2x+8)(x-1)

x=-4 x=1

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3 years ago

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In the calm waters of an inlet, Manon's boat moves with a velocity (speed and direction) vector \vec{b_1} = (3,4) b 1 =(3,4)

andrew-mc [135]

Answer with Step-by-step explanation:

We are given that

$b_1=(3,4)$

$b_2=(1,1)$

We have to find the speed of river's current and the direction of current flowing.

$b=b_2-b_1=(1,1)-(3,4)=(-2,-3)$

Speed of river's current= $\mid b\mid$

Speed of river's current= $\sqrt{(-2)^2+(-3)^2}$

Speed of river's current= $\sqrt{13} m/s$

By using the formula

$\mid r\mid =\sqrt{x^2+y^2}$

Direction of current flowing, $\theta=tan^{-1}(\frac{y}{x})$

$\theta=tan^{-1}(\frac{-3}{-2})=56.3^{\circ}$

The angle lies in third quadrant therefore

$\theta=180+56.3=236.3^{\circ}$

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3 years ago