Answer: no
Step-by-step explanation:
Answer:
Rider 1 does one round in 15 min, and will complete another in each consecutive multiple of 15 min
Rider 2 does one round in 18 min, and will complete another in each consecutive multiple of 18 min
Assuming that they start together, they will complete another round together in a time that is both multiples of 15min and 18 min.
Then we need to find the smallest common multiple between 15 and 18.
To smallest common multiple between two numbers, a and b, is equal to:
a*b/(greatest common factor between a and b).
Now, the greatest common factor between 15 and 18 can be found if we write those numbers as a product of prime numbers, such as:
15 = 3*5
18 = 2*3*3
The greatest common factor is 3.
Then the smallest common multiple will be:
(15*18)/3 = 90
This means that after 90 mins, they will meet again at the starting place.
Given the function. y = 3x + 5
For, x = -3; y = 3(-3) + 5 = -9 + 5 = -4
For x = 1; y = 3(1) + 5 = 3 + 5 = 8
For x = 4; y = 3(4) + 5 = 12 + 5 = 17
Thus the table representing the function is the table with: -3, 1 and 4 as x-values and -4, 8, 17 as y-values.
For x = 0; y = 3(0) + 5 = 0 + 5 = 5
For y = 0; 0 = 3x + 5; 3x = -5 and x = -5/3
Thus the graph of the function is a straight line passing through points (0, 5) and (-5/3, 0).
To illustrate the fuction as a word statement we say that y is five more than three times x
From the given descriptions, the graph does not represent the graph of y = 3x + 5.
Therefore, the one that does not describe the same situation is the graph.
Divide 1080 by 1+3+5 which is 9
120 is 1
360 is 3
600 is 5
120:360:600
