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3 years ago

Evaluate the expressio -6(-5)+12

Mathematics

2 answers:

natta225 [31]3 years ago

6 0

First, multiply -6*-5. This equals (positive) 30 because the negative signs cancel out.

This leaves you with:

30+12

Doing the addition leaves you with 42.

The answer is 42.

I hope this helps :)

Aneli [31]3 years ago

5 0

-6(-5)+12

Do first the parenthesis

30+12

Add 30 &12

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ruslelena [56]

Hi there!

When we have an equation standard form...
$a {x}^{2} + bx + c = 0$
...the formula of the discriminant is
D = b^2 - 4ac

When
D > 0 we have two real solutions
D = 0 we have one real solutions
D < 0 we don't have real solutions

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Plug in the values from the equation into the formula of the discriminant

$( - 8) {}^{2} - 4 \times 1 \times 7 = 64 - 28 = 36$

D > 0 and therefore we have two real solutions.

2.) Find the value of the discriminant and the number of real solutions of
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${4}^{2} - 4 \times 2 \times 2 = 16 - 16 = 0$

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~ Hope this helps you.

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2 years ago

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(x-1)(x-3)(x+5)(x+7)=297

mihalych1998 [28]

First simplify the expression into polynomial form,

$(x-1)(x-3)(x+5)(x+7)=297$

$x^4+8x^3-10x^2-104x+105=297$

$x^4+8x^3-10x^2-104x-192=0$

Now factor into,

$(x-4)(x+8)(x^2+4x+6)=0$

Which means the solutions are,

$x-4=0\implies\boxed{x_1=4}$

$x+8=0\implies\boxed{x_2=-8}$

and then two complex solutions because determinant of the third factor $D\lt0$ ,

$x^2+4x+6=0$

$x^2+4x+4=-2$

$(x+2)^2=-2\implies\boxed{x_3=i\sqrt{2}-2},\boxed{x_4=-i\sqrt{2}-2}$

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3 years ago

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Write the equation of the line in slope- intercept and point-slope form.

AnnZ [28]

Answer:

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