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3 years ago

How to simplify 2^4 ÷ 2^10

Mathematics

1 answer:

bearhunter [10]3 years ago

6 0

2^(-6) or 1/(2^6) . You can pick either one

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Color-blindness is any abnormality of the color vision system that causes a person to see colors differently than most people or

Veronika [31]

Answer:

Correct option is (d): Neither X nor Y can be well-approximated by a normal random variable.

Step-by-step explanation:

The sample size of males having color-blindness is, n (X) = 20.

The sample size of females having color-blindness is, n (Y) = 40.

The proportion of males that suffer from color-blindness is, P (X) = 0.08.

The proportion of females that suffer from color-blindness is, P (Y) = 0.01.

Now both the random variables X and Y follows a Binomial distribution,

$X\sim Bin(20, 0.08)\\Y\sim Bin(40, 0.01)$

A normal distribution is used to approximate the binomial distribution if the sample is large, i.e n ≥ 30 and the probability of success is very close to 0.50.

Also if np ≥ 10 and n (1 - p) ≥ 10, the binomial distribution can be approximated by the normal distribution.

For the sample of men (X):

$np=20\times0.08=1.610$

In this case neither n > 30 nor p is close to 0.50.

And np < 10.

Thus, the random variable X cannot be approximated by the normal distribution.

For the sample of men (Y):

$np=40\times0.01=0.410$

In this case n > 30 but p is not close to 0.50.

And np < 10.

Thus, the random variable Y cannot be approximated by the normal distribution.

Thus, both the random variables cannot be approximated by the normal distribution.

The correct option is (d).

3 0

4 years ago

Obtuse is to more than 90° as reflex is to

Simora [160]

9514 1404 393

Answer:

>180° (more than 180°)

Step-by-step explanation:

Angles are classified as ...

acute: < 90°
right: = 90°
obtuse: > 90°
straight/linear: = 180°
reflex: > 180°

It seems that we're looking at definitions:

obtuse : >90° :: reflex : >180°

7 0

3 years ago

Given <img src="https://tex.z-dn.net/?f=f%28x%29%20%3Dx%5E2%20-6x%2B8%20and%20g%28x%29%20%3Dx-2" id="TexFormula1" title="f(x) =x

Eva8 [605]

For this case we have the following functions:

$f (x) = x ^ 2-6x + 8\\g (x) = x-2$

We must subtract the functions:

$f (x) -g (x) = x ^ 2-6x + 8- (x-2)\\f (x) -g (x) = x ^ 2-6x + 8-x + 2\\f (x) -g (x) = x ^ 2-7x + 10$

We build a table of values for $x = 0,1,2,3.$

$x = 0, f (x) -g (x) = 0 ^ 2-7 (0) + 10 = 10\\x = 1, f (x) -g (x) = 1 ^ 2-7 (1) + 10 = 1-7 + 10 = 4\\x = 2, f (x) -g (x) = 2 ^ 2-7 (2) + 10 = 4-14 + 10 = 0\\x = 3, f (x) -g (x) = 3 ^ 2-7 (3) + 10 = 9-21 + 10 = -2$