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4 years ago

Prime factorization of 1296

Mathematics

1 answer:

EleoNora [17]4 years ago

8 0

Answer:2^4*3^4 or 2*2*2*2*3*3*3*3

Step-by-step explanation: I’m lazy here’s the answer^

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Evaluate 4.1 + 6. 16 + 0.

Musya8 [376]

The answer to 4.1+6.16+0. Is 10.26

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4 years ago

Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, of all homeowners are insured

ANTONII [103]

Missing part of the question

Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, 25% of all homeowners.....................

Answer:

$P(X = x) = ^4C_x * 0.25^x * 0.75^{4-x}$

$Mean = 1$

$Pr = 0.2617$

Step-by-step explanation:

Given

$n = 4$

$p = 25\%$

Solving (a): The probability distribution of x

We have:

$n = 4$

$p = 25\%$ $= 0.25$

The probability of not having earthquake insurance (q) is:

$q = 1 - p$

$q = 1 - 0.25$ $= 0.75$

If x has insurance, then n - x do not.

The distribution follows a binomial pattern. So, the probability distribution is:

$P(X = x) = ^nC_x * 0.25^x * 0.75^{n-x}$

Substitute 4 for n

$P(X = x) = ^4C_x * 0.25^x * 0.75^{4-x}$

Solving (b): The most likely value of x i.e. The mean

We have:

$n = 4$ and

$p = 25\%$ $= 0.25$

$Mean = np$

$Mean = 4 * 0.25$

$Mean = 1$

Solving (c): At least 2 of 4 selected have earthquake insurance.

This is calculated as

$Pr = P(x = 2) + P(x = 3) + P(x = 4)$

$P(X = x) = ^4C_x * 0.25^x * 0.75^{4-x}$

$P(X=2) = ^4C_2 * 0.25^2 * 0.75^{4-2}$

$P(X=2) = 6 * 0.25^2 * 0.75^2 = 0.2109375$

$P(X=3) = ^4C_3 * 0.25^3 * 0.75^{4-3}$

$P(X=3) = 4 * 0.25^3 * 0.75 = 0.046875$

$P(X=4) = ^4C_4 * 0.25^4 * 0.75^{4-4}$

$P(X=4) = 1 * 0.25^4 * 1= 0.00390625$

So:

$Pr = P(x = 2) + P(x = 3) + P(x = 4)$

$Pr = 0.2109375 + 0.046875 + 0.00390625$

$Pr = 0.26171875$

$Pr = 0.2617$ --- approximated

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3 years ago

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lilavasa [31]

Answer: OPTION D.

Step-by-step explanation:

The symbol of the inequality ">" means "greater than". Then, -5 is greater than -6.

If a negative number -a is greater than other negative number -b , then the distance between -a and zero is shorter than the distance between -b and zero.

You can see in the number line attached that -5 is closer to 0 than -6. Therefore, -5 is located to the right of -6.

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