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SashulF [63]
4 years ago
8

Prime factorization of 1296

Mathematics
1 answer:
EleoNora [17]4 years ago
8 0

Answer:2^4*3^4 or 2*2*2*2*3*3*3*3

Step-by-step explanation: I’m lazy here’s the answer^

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4 years ago
Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, of all homeowners are insured
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Missing part of the question

Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, 25% of all homeowners.....................

Answer:

P(X = x) = ^4C_x * 0.25^x * 0.75^{4-x}

Mean = 1

Pr = 0.2617

Step-by-step explanation:

Given

n = 4

p = 25\%

Solving (a): The probability distribution of x

We have:

n = 4

p = 25\% = 0.25

The probability of not having earthquake insurance (q) is:

q = 1 - p

q = 1 - 0.25 = 0.75

If x has insurance, then n - x do not.

The distribution follows a binomial pattern. So, the probability distribution is:

P(X = x) = ^nC_x * 0.25^x * 0.75^{n-x}

Substitute 4 for n

P(X = x) = ^4C_x * 0.25^x * 0.75^{4-x}

Solving (b): The most likely value of x i.e. The mean

We have:

n = 4 and

p = 25\% = 0.25

Mean = np

Mean = 4 * 0.25

Mean = 1

Solving (c): At least 2 of 4 selected have earthquake insurance.

This is calculated as

Pr = P(x = 2) + P(x = 3) + P(x = 4)

P(X = x) = ^4C_x * 0.25^x * 0.75^{4-x}

P(X=2) = ^4C_2 * 0.25^2 * 0.75^{4-2}

P(X=2) = 6 * 0.25^2 * 0.75^2 = 0.2109375

P(X=3) = ^4C_3 * 0.25^3 * 0.75^{4-3}

P(X=3) = 4 * 0.25^3 * 0.75 = 0.046875

P(X=4) = ^4C_4 * 0.25^4 * 0.75^{4-4}

P(X=4) = 1 * 0.25^4 * 1= 0.00390625

So:

Pr = P(x = 2) + P(x = 3) + P(x = 4)

Pr = 0.2109375 + 0.046875 + 0.00390625

Pr = 0.26171875

Pr = 0.2617 --- approximated

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3 years ago
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Answer: OPTION D.

Step-by-step explanation:

The symbol of the inequality ">" means "greater than". Then, -5 is greater than -6.

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You can see in the number line attached that -5 is closer to 0 than -6. Therefore, -5 is located to the right of -6.

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