By algebra properties we find the following relationships between each pair of algebraic expressions:
- First equation: Case 4
- Second equation: Case 1
- Third equation: Case 2
- Fourth equation: Case 5
- Fifth equation: Case 3
<h3>How to determine pairs of equivalent equations</h3>
In this we must determine the equivalent algebraic expression related to given expressions, this can be done by applying algebra properties on equations from the second column until equivalent expression is found. Now we proceed to find for each case:
First equation
(7 - 2 · x) + (3 · x - 11)
(7 - 11) + (- 2 · x + 3 · x)
- 4 + (- 2 + 3) · x
- 4 + (1) · x
- 4 + (5 - 4) · x
- 4 - 4 · x + 5 · x
- 4 · (x + 1) + 5 · x → Case 4
Second equation
- 7 + 6 · x - 4 · x + 3
(6 · x - 4 · x) + (- 7 + 3)
(6 - 4) · x - 4
2 · x - 4
2 · (x - 2) → Case 1
Third equation
9 · x - 2 · (3 · x - 3)
9 · x - 6 · x + 6
3 · x + 6
(2 + 1) · x + (14 - 8)
[1 - (- 2)] · x + (14 - 8)
(x + 14) - (8 - 2 · x) → Case 2
Fourth equation
- 3 · x + 6 + 4 · x
x + 6
(5 - 4) · x + (7 - 1)
(7 + 5 · x) + (- 4 · x - 1) → Case 5
Fifth equation
- 2 · x + 9 + 5 · x + 6
3 · x + 15
3 · (x + 5) → Case 3
To learn more on algebraic equations: brainly.com/question/24875240
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1. in picture 1
2. in picture 2
Hope this helps :T
Also I am not so shure about 2, but I am 98% shure 1 is right.
Answer:
The probability of spinning a vowel, then Q, is 1/12
Step-by-step explanation:
Find the probability of each event occurring. There are three vowels out of 6 letters and 1 Q, so the chances of spinning a vowel is 3/6 or 1/2 and the chances of spinning a Q is 1/6. Multiply the probabilities of the two events occurring to find the probability of a compound event. 1/2*1/6 = 1/12. Hope this helps!
Distribute ^4 to both 2 and q^5
2^4 = 2 x 2 x 2 x 2 = 16
(q^5)^4 = q^20
16(q^20) = 16q^20
16q^20 is your answer
hope this helps
