Multiple this complex number (4-3i)^2

Mathematics

2 answers:

hram777 [196]3 years ago

6 0

7 - 24<em>i</em>

Step-by-step explanation:

(4−3i)(4−3i)(4-3i)(4-3i).

(4−3i)(4−3i)(4-3i)(4-3i)

Expand (4−3i)(4−3i)(4-3i)(4-3i) using the FOIL Method.

Apply the distributive property.

4(4−3i)−3i(4−3i)4(4-3i)-3i(4-3i)

Apply the distributive property.

4⋅4+4(−3i)−3i(4−3i)4⋅4+4(-3i)-3i(4-3i)

Apply the distributive property.

4⋅4+4(−3i)−3i⋅4−3i(−3i)4⋅4+4(-3i)-3i⋅4-3i(-3i)

Simplify and combine like terms

slava [35]3 years ago

5 0

Answer is 7-24i tehe

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