To find the rate, you must divide the distance traveled by the time it took.
17.5 m is the distance while time it took was 5 seconds.
So,
17.5 ÷ 5 = 3.5 m/s
The rate of the anchor is 3.5 m/s
Note: I did not ignore the negative sign in the distance but rather acknowledged it as a magnitude. This meant that the anchor was dropping down instead of going up.
<span>Reading the solution, please, look on the picture)
Let the side of the square will be X meters. This means that S1=x^2 </span>meters ^2<span>
One side of </span>new rectangular garden will be 2x meters and another (x-3) meters. So S2=2x(x-3) meters ^2
According to the <span>data:
</span><span>S1*1.25=S2
</span>x^2*1.25=<span>2x(x-3)
</span>1.25*x^2=2x^2-6x
0.75x^2-6x=0
3x^2-24x=0
x^2-8x=0
x(x-8)=0
x=8 or x=0
But x>0!
So x = 8 meters
The next question is to find S2.
S2=2x(x-3)=2*8*5=80 meters ^ 2
Answer:
i the that should be -1.1
Answer:
The result gives the equation: 9x = -7
solution: (-7/9, 4/3)
Step-by-step explanation:
6 x + 2y = − 2
and
3 x − 2y = − 5
add together
6x + 3x + 2y - 2y = -2 + -5
9x + 0 = -7
9x = -7
then x = -7/9
and y = -3x - 1:
y = -3*(-7/9) - 1
y = 7/3 - 1 = 4/3
solution: (-7/9, 4/3)
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6x+2y= -2 and 3x−2y =−5
6x + 3x + 2y - 2y = -2 + -5
The answer to your question is
24