Question

Employees were asked how many times per week they exercised. The frequency table shows the results of the survey.

Answer 1

Answer:

See explanation

Step-by-step explanation:

Given the frequency table

$\begin {array}{cccccccccc}\text{Number}&0&1&2&3&4&5&6&7&8\\ \\\text{Frequency}&5&10&2&9&33&12&15&3&1\end{array}$

a) The total sum is

$5+10+2+9+33+12+15+3+1=90$

Create a probability distribution table

$\begin {array}{cccccccccc}\text{Number}&0&1&2&3&4&5&6&7&8\\ \\\text{Probability}&\dfrac{5}{90}&\dfrac{10}{90}&\dfrac{2}{90}&\dfrac{9}{90}&\dfrac{33}{90}&\dfrac{12}{90}&\dfrac{15}{90}&\dfrac{3}{90}&\dfrac{1}{90}\end{array}$

b) The probability

$P(x$

c) The probability

$P(x=6)=\dfrac{15}{90}=\dfrac{1}{6}$

d) The probability

$P(x\ge 5)=P(x=5)+P(x=6)+P(x=7)+P(x=8)=\dfrac{12}{90}+\dfrac{15}{90}+\dfrac{3}{90}+\dfrac{1}{90}=\dfrac{31}{90}$