Answer:
168cm^3
Step-by-step explanation:
Q to P is going to be 3cm. it is identical to the length T to U.
R to T , W to Q, S to U is going to be identical to P to V. P to V has been identified as 12 cm.
in the middle of the shape, there are 4 identical triangles. the height time length will give us the area of that one shape:
e.g for shape P to V to W to Q and back to P is one rectangle. the length is 12 cm and the width is 3 cm.
12 x 3= 36
36cm^3 is one rectangles surface area, we have 4 identical triangles that means we need to times 36 by 4.
so 36x4=144.
now on the left and right side, we have two squares. on the right, we have T to U to V to W back to T this has the height of 3 width of 4 then we do 3 X 4 which is 12, we times it by 2 because we have two identical squares.
12 X 2=24
finally we add 24 and 144 = 168cm^3.
hope this helps :)
Answer: I need the diagram of the figure that the two angles are on.
Step-by-step explanation:
Domain:
This function is a polynomial, i.e. a sum of powers of a variables, each with its coefficient. Polynomials are defined for every possible value of the variable, so the domain is the whole real number set: 
Range:
A polynomial of degree 2 represents a parabola. Since the leading coefficients, i.e. the coefficient of the term with highest degree, is positive (in this case, it's 3), the parabola is concave up. It means that it has a minimum, and it's unbounded from above. So, the range is something like 
. To find the minimum, let's start with the "standard" parabola 
, and transform it to the one of this exercise. has minimum 0, and thus its range is 
. When you multiply it times three, its shape narrows, but the range wont change: 
. Finally, when you subtract 5, you shift everythin down 5 units. This transformation affects the range, since you have 
Image of -3:
To compute 
, simply plug 
in the formula:
Numbers associated with 43:
We want to see which x value we must choose to get a y value of 43. So, the equation is
The answer to your question is 260
