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denpristay [2]
4 years ago
9

In a list of 200 numbers,each number after the first is 4 more then the number that comes before it.What is the difference betwe

en the first and the last number on this list?
Mathematics
1 answer:
9966 [12]4 years ago
3 0
Let a₁ = the first number.

Because each number is 4 more than the number before it, the list of numbers forms an arithmetic sequence with a common difference of d = 4.

The n-th term is
a_{n} = a_{1}+(n-1)d

The 200-th term is
a₂₀₀ = a₁ + (200 - 1)*4
      = a₁ + 796
a₂₀₀ - a₁ = 796

Because a₂₀₀ is the last number on the list, the difference between the first and the last number on the list is 796.

Answer: The difference is 796.

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BartSMP [9]
Convert 150mm into cm = 15cm   
So 15cm to 60cm 
Divide by 15
B. 1 to 4
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4 0
2 years ago
Read 2 more answers
Peter selects a sock from his drawer. The sock is black. There are 4 white socks, 7 blue socks, and 12 black socks left in the d
max2010maxim [7]

Answer:

5/12

7/12

125/36 = 3,47%

50/11 = 4,54%

Step-by-step explanation:

Probability a black sock is selected when a person chooses 1 sock = 5/12

Probability a white or brown sock is selected when a person chooses 1 sock =

7/12

Probability  a person chooses 3 socks and selects a white first, a black second, and a brown last if the socks are replace = (4/12 * 5/12 * 3/12)*100 =125/36 = 3,47%

Pobability  a person chooses 3 socks and selects a white first, a black second, and a brown last if the socks are NOT replace = (4/12 * 5/11 * 3/ 10)*100 = 50/11 = 4,54%

3 0
3 years ago
Need help with this problem ,please and THANK YOU :)
KiRa [710]

Answer:

A

Step-by-step explanation:

8 0
3 years ago
Is the following statement correct? Explain.
Maksim231197 [3]

Answer:  The answer is NO.


Step-by-step explanation: The given statement is -

If the graph of two equations are coincident lines, then that system of equations will have no solution.

We are to check whether the above statement is correct or not.

Any two equations having graphs as coincident lines are of the form -

ax+by=c,\\\\dax+dby=dc,\\\\\textup{where}~~d\neq 1.

If we take d = 1, then both the equations will be same.

Now, subtracting the second equation from first, we have

a(1-d)x+b(1-d)y=c(1-d)\\\\\Rightarrow ax+by=c,~\textup{since}~d\neq 1,~\textup{so}~1-d\neq 0.

Again, we will get the first equation, which is linear in two unknown variables. So, the system will have infinite number of solutions, which consists of the points lying on the line.

For example, see the attached figure, the graphs of following two equations is drawn and they are coincident. Also, the result is again the same straight line which has infinite number of points on it. These points makes the solution for the following system.

2x+5y=10,\\\\6x+15y=30.

Thus, the given statement is not correct.


4 0
3 years ago
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