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goldfiish [28.3K]
2 years ago
11

A college student earned $5100 during summer vacation working as a waiter in a restaurant on the boardwalk at the beach. The stu

dent invested part of the money at 8% and the rest at 9%. If the student received a total of $445 in interest at the end of the year, how much was invested at 9%?
Mathematics
1 answer:
Mama L [17]2 years ago
6 0
<h3>Answer:</h3>

$3700

<h3>Step-by-step explanation:</h3>

Let x represent the amount invested at 9%. Then 5100-x is the amount invested at 8%. The total interest earned is ...

... 0.08(5100-x) +0.09x = 445

... 0.01x = 445 -0.08·5100 . . . . . collect terms, subtract .08·5100

... x = (445 -408)/0.01 = 3700 . . . divide by the coefficient of x.

The student invested $3700 at 9%.

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The graph of the line with the equation y = 1/2 * x + 4 crosses the x-axis at which of the following
svlad2 [7]

Answer:

Step-by-step explanation:

so we are looking for the x intercept (where the line crosses the x axis).

to do this, we sub in 0 for y and solve for x.

y = 1/2x + 4....sub in 0 for y

0 = 1/2x + 4

-1/2x = 4

x = 4 * -2

x = -8 <=== so it crosses the x axis at (-8,0)

5 0
3 years ago
Every natural number is a whole number true or false​
bija089 [108]

Answer:

true

Step-by-step explanation:

it is what it is

5 0
3 years ago
Read 2 more answers
Find the horizontal and vertical asymptotes of​ f(x). ​f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the
miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* <em>Lets the meaning of vertical and horizontal asymptotes</em>

- <u><em>Vertical asymptotes</em></u> are vertical lines which correspond to the zeroes

  of the denominator of a rational function

- <u><em>A horizontal asymptote</em></u> is a y-value on a graph which a function

 approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

 denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

 denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

 then there is a horizontal asymptote at y = leading coefficient of the

 numerator ÷ leading coefficient of the denominator

* <em>Lets solve the problem</em>

∵ f(x)=\frac{6x}{x+2}

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ <em>The horizontal asymptote can be described by the line y = 6</em>

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ <em>The vertical asymptote can be described by the line x = -2</em>

6 0
2 years ago
Read 2 more answers
2. Calculate the energy in joules of a photon whose frequency is 7.55×1014 Hz.
igomit [66]
The energy of a photon is given by
E = h × v

where:
E is the energy in joules/photon
'h' is the constant 6.63 × 10⁻³⁴
'v' is the frequency 7.55 × 10¹⁴

Substitute 'h' and 'v' into the formula we have

E = (6.63×10⁻³⁴) × (7.55×10¹⁴)
E = (6.63×7.55) × (10⁻³⁴ × 10¹⁴)
E = 50.0565 × 10⁽⁻³⁴⁺¹⁴⁾
E = 50 × 10⁻²⁰ joules/photon
8 0
3 years ago
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SpyIntel [72]

Answer:

Yes .The Pythagorean equation is true.

Step-by-step explanation:

yes, they can, because of the equation below :

a² = b² + c²

40² = 32² + 24²

1600 = 1024 + 576

1600 = 1600 ✓

7 0
1 year ago
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