A college student earned $5100 during summer vacation working as a waiter in a restaurant on the boardwalk at the beach. The stu dent invested part of the money at 8% and the rest at 9%. If the student received a total of $445 in interest at the end of the year, how much was invested at 9%?
1 answer:
<h3>
Answer: </h3>
$3700
<h3>
Step-by-step explanation: </h3>
Let x represent the amount invested at 9%. Then 5100-x is the amount invested at 8%. The total interest earned is ...
... 0.08(5100-x) +0.09x = 445
... 0.01x = 445 -0.08·5100 . . . . . collect terms, subtract .08·5100
... x = (445 -408)/0.01 = 3700 . . . divide by the coefficient of x.
The student invested $3700 at 9% .
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