Need Help Please Answer asap anyone

Mathematics

1 answer:

balandron [24]3 years ago

8 0

It is the D answer.

Even though I cannot see the second equation, I know that this must be it. It is the only set of equations that properly states that she must work less than 15 hours combined (b + t)

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12.3 Write the first five terms of the sequence whose general term is <img src="https://tex.z-dn.net/?f=a_%7Bn%7D%3D3%5E%7Bn%7D%

weeeeeb [17]

Answer:

7,13,31,85,247......

Step-by-step explanation:

$a_n =3^n + 4$

$\sf a_1=3^1 + 4 = 3 + 4 = 7\\\\a_2 = 3^2 + 4 = 9 + 4 = 13\\\\a_3 = 3^3 + 4 = 27 + 4 = 31\\\\a_4 = 3^4 + 4 = 81 + 4 = 85\\\\a_5 = 3^5 + 4 = 243 + 4 = 247$

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Read 2 more answers

How do you solve cos(pi/24) using Half-Angle formulas, and leaving in simplified form?

adoni [48]

$\cos \frac{\theta}{2}=\sqrt{\frac{1+\cos \theta}{2}}
\\
\\ \cos{\frac{\pi}{24}}=\cos{\frac{\frac{\pi}{12}}{2}}=\sqrt{\frac{1+\cos \frac{\pi}{12}}{2}}= \sqrt{ \frac{1}{2}+ \frac{\cos \frac{\pi}{12}}{2} } 
\\
\\ \cos{\frac{\pi}{12}}=\cos{\frac{\frac{\pi}{6}}{2}}=\sqrt{\frac{1+\cos \frac{\pi}{6}}{2}}= \sqrt{ \frac{1}{2}+ \frac{ \frac{ \sqrt{3} }{2} }{2} } =\sqrt{ \frac{2}{4}+ \frac{ \sqrt{3} }{4} } = \sqrt{\frac{ 2+\sqrt{3} }{4} } = 
\\
\\ =\frac{ \sqrt{2+\sqrt{3}} }{2} 
$

$\cos{\frac{\pi}{24}}= \sqrt{ \frac{1}{2}+ \frac{\cos \frac{\pi}{12}}{2} } = \sqrt{ \frac{1}{2}+ \frac{\frac{ \sqrt{2+\sqrt{3}} }{2}}{2} } = \sqrt{ \frac{2}{4}+ \frac{ \sqrt{2+\sqrt{3}} }{4}} } =\sqrt{ \frac{ 2+\sqrt{2+\sqrt{3}} }{4}} } 
\\
\\\cos{\frac{\pi}{24}}=\frac{\sqrt{2+\sqrt{2+\sqrt{3}}}} {2}$

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3 years ago