Following are the "dice_eval" method code into python language.
Program Explanation:
- Defining a method "dice_eval" that takes two variables "d1,d2" in its parametes.
- Inside the method, multiple conditional statements were used that adds the parameter values and calculates its value which can be defined as follows:
- In the if block, it adds the parameters and uses or gate that check its value that is equal to 7 or 11. so, it will return a string message that is 'Winner!'.
- In the elif block, it adds the parameters and uses or gate that check its value that is equal to 2 or 3 or 12. so, it will return a string message that is ' C r aps ! '.
- In the else block, it uses a return keyword that adds parameter value and prints a string value.
- Outside the method "d1,d2" is declared that inputs the value from the user-end, and passes the value into the method, and prints its value.
Program:
def dice_eval(d1, d2):#defining a method dice_eval that takes two parameters
if (d1+d2)==7 or (d1+d2)==11:#defining if block that adds parameter value and use or operator to check its value
return 'Winner!'#return string value
elif (d1+d2)==2 or (d1+d2)==3 or (d1+d2)==12:#defining elif block that adds parameter value and use or operator to check its value
return 'C r aps!'#return string value
else:#defining else block
return 'Point is '+str(d1+d2)#return string value with adding parameter
d1=int(input())#defining d1 that input value
d2=int(input())#defining d2 that input value
print(dice_eval(d1,d2))#calling method and print its return value
Output:
Please find the attached file
Please find the complete code in the attached file.
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brainly.com/question/15011927
Answer:
the MAC addresses of wireless NICs
Explanation:
Answer:
true
Explanation:
The given operators && and || are Logical operators whose execution is from left to right.so first (x>=10)&&(y>20) will be executed .Given values for x and y are 10 ,20 (10>=10 true)&&(10>20 false), which gives result as false (&& evaluates to true only when both conditions are true).so the result of this is false. next condition is ||. for this (20>=10)&&(20>20) is false and (x<y)(10<20) is true, which gives result as true.(|| evaluates to true if any one is true).
The Answer is True