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Ostrovityanka [42]
3 years ago
8

if a network security professional wants to connect some computers in the same building without it using a router what type of n

etwork is being used
Computers and Technology
2 answers:
marta [7]3 years ago
8 0

Answer:

 the MAC addresses of wireless NICs

Explanation:

snow_lady [41]3 years ago
6 0

Answer:

I would probably suggest <u>Peer-to-Peer</u>

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Which of the following is NOT a factor that increases the health risks of construction workers?
Nadya [2.5K]

From all the available options, the one that would not increase the health risk for construction workers would be (D) stable, rarely changing job site environments and conditions.

High number of unskilled labors increase the likelihood that an accident might occur, while high turnover creates instability which in turn might increase the same likelihood due to increased workload while human resources seek a replacement. Multiple contractors and subcontractors mean confusions might arise and accident may likely happen if the risk is not properly managed.

8 0
3 years ago
Read 2 more answers
Write a code that calculates the Greatest Common Divisor (GCD) of two positive integers (user-defined inputs). Include an except
STALIN [3.7K]

Answer:

<em>This program is written using Java programming language</em>

import java.util.*;

public class calcGcd

{

   public static void main (String [] args)

   {

       int num1, num2;

       Scanner input = new Scanner(System.in);

       //Input two integers

       num1 = input.nextInt();

       num2 = input.nextInt();

       //Get least of the two integers

       int least = num1;

       if(num1 > num2)

       {

           least = num2;

       }

       //Initialize gcd to 1

       int gcd = 1;

       //Calculate gcd using for loop

       for(int i=1;i<=least;i++)

       {

           if(num1%i == 0 && num2%i == 0)

           {

               gcd = i;

           }

       }

       if(gcd == 1)

       {

           System.out.print("GCD is 1");

       }

       else

       {

           System.out.print("GCD is "+gcd);

       }

   }

}

Explanation:

To calculate the GCD, the program uses a for loop that iterates from 1 to the smaller number of the user input.

Within this iteration, the program checks for a common divisor of the two user inputs by the iterating element

The GCD is then displayed afterwards;

However, if the GCD is 1; the program prints the message "GCD is 1"

<em>Line by Line Explanation</em>

This line declares two integer numbers

       int num1, num2;

This line allows user the program to accept user defined inputs        

Scanner input = new Scanner(System.in);

The next two line allows gets inputs from the user

<em>        num1 = input.nextInt();</em>

<em>        num2 = input.nextInt();</em>

<em />

To calculate the GCD, the smaller of the two numbers is needed. The smaller number is derived using the following if statement

<em>        int least = num1;</em>

<em>        if(num1 > num2)</em>

<em>        {</em>

<em>            least = num2;</em>

<em>        }</em>

The next line initializes GCD to 1

       int gcd = 1;

The GCD is calculated using the following for loop

The GCD is the highest number that can divide both numbers

<em>        for(int i=1;i<=least;i++)</em>

<em>        {</em>

<em>            if(num1%i == 0 && num2%i == 0)</em>

<em>            {</em>

<em>                gcd = i;</em>

<em>            }</em>

<em>        }</em>

The following is printed if the calculated GCD is 1

       if(gcd == 1)

       {

           System.out.print("GCD is 1");

       }

Otherwise, the following is printed

       else

       {

           System.out.print("GCD is "+gcd);

       }

8 0
3 years ago
I need app ideas please help​
Artemon [7]

Answer:

I have a few ideas although most are simple and for nothing too useful

1. ghost simulator (you can like haunt people and mess with all their stuff and the more u f with them tge more points and the higher level u get you get more power and more ability to mess with things like eventually you'll be able to possess things and ig the goal wou.d be to either kill the person living in your house or scare them until they run away and there can be little side missions for like extra points and accessories n stuff)

2. my forest (you have workers that make money and the more money you get the more stuff u can buy for your forest and you can customize it and it's pretty much like a therapeutical thing where you can make a pretty forest w mystical creatures and stuff

3. egg (its literally just an egg on the screen that's it there is just an egg)

Explanation:

first things that came to mind I just like brainstorming at these kinda things lmk if u plan on using any aspect of my ideas I'd love to see your app

4 0
3 years ago
What does it mean when information found from web research is valid?
Mrac [35]

Answer:

The information comes from an official source.

5 0
3 years ago
The instruction format of a computer is given by one indirect bit, opcode bits, register address bits, immediate operand bits an
oksian1 [2.3K]

Answer:

Following are the answer to this question:

Explanation:

A)

The memory size is 1 Giga Bytes which is equal to 2^{30}

\texttt{Number of address bits    \ \ \ \ \ \ \ \ \ \ \ \ \ \            Number of addresses}\\\\ \ \ \ \ 30  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \                                 2^{30}= 1073741824

B) \texttt{I \ \ \ Opcode  \ \ \ Register address \ \ \  Immediate operand \ \ \    Memory address}\\\\\\\textt{1 \ bit  \  \ \ \ \ \ 128  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \    2 \ bits   \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \   24 \ bits  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \           30 \ bits}\\\\\\            = 2^7 \\\\ = 7 \ bits

calculating the register Bits:

= 64-(1+7+24+30)\\\\=64 -62\ \  bits\\\\= 2\ \ bits\\

C)

Immediate value size while merging the additional benefit with the address field:

= 2^{24} + 2^{30}\\\\= 2^{54}\\\\\texttt{Range before combining(-,+) 24 bits   \ \ \ \ \ \       Range after combining( -,+)54bits}\\\\                         \textt{-2^{12} from + (2^{12}-1)   \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \                                    -2^{27} from + (2^{27}- 1)}

= \frac{24}{2} = 12\\\\= \frac{54}{2} = 27

The range is accomplished by dividing the bits by 2 into the two sides of the o and the number is one short to 0.

8 0
3 years ago
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