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Alenkasestr [34]
3 years ago
7

Simplify fraction 7 / 27

Mathematics
2 answers:
Soloha48 [4]3 years ago
8 0
This fraction is already in simplest form.


As a decimal is 0.259..



pshichka [43]3 years ago
8 0
That fraction is already simplified.
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Are there always the same number of prime numbers between 2 consecutive multiples of 10? Why?
galina1969 [7]

Answer:

Yes it is 5

Step-by-step explanation:

It is 5 because you divide 2 and 10 and it is 5

4 0
4 years ago
PERSON GETS 15 POINTZ PLZ HURRY The mean of the list n, n + 3, n+4, n+5, n+6, n+8, n+10, n + 12, n+15 is 11. What is the median?
7nadin3 [17]

Answer:

10

Step-by-step explanation:

To find the value of n we can write:

(n + n + 3 + n + 4 + n + 5 + n + 6 + n + 8 + n + 10 + n + 12 + n + 15) / 9 = 11

(9n + 63) / 9 = 11

9n + 63 = 99

9n = 36

n = 4

The median is n + 6 which is 4 + 6 = 10.

7 0
3 years ago
Read 2 more answers
Simplify.<br> Rewrite the expression in the form b^n<br><br> (b^3)^2
Alexxandr [17]

Step-by-step explanation:

a^n={\underbrace{a\cdot a\cdot a\cdot...\cdot a}_{n}

<h2>METHOD 1.</h2>

\left(b^3\right)^2=\underbrace{b^3\cdot b^3}_{2}=\underbrace{b\cdot b\cdot b}_{3}\cdot\underbrace{b\cdot b\cdot b}_{3}=\underbrace{b\cdot b\cdot b\cdot b\cdot b\cdot b}_{6}=b^6

<h2>METHOD 2.</h2>

\left(b^3\right)^2=\underbrace{b^3\cdot b^3}_{2}=b^{3+3}=b^6\qquad\text{used}\ a^n\cdot a^m=a^{n+m}

<h2>METHOD 3.</h2>

\left(b^3\right)^2=\left(\underbrace{b\cdot b\cdot b}_{3}\right)^2=b^2\cdot b^2\cdot b^2=b^{2+2+2}=b^6\\\text{used}\ (ab)^n=a^nb^n,\ a^n\cdot a^m=a^{n+m}

<h2>METHOD 4.</h2>

\left(b^3\right)^2=b^{3\cdot2}=b^6\qquad\text{used}\ \left(a^n\right)^m=a^{nm}

5 0
3 years ago
which function has real zeros at x = −10 and x = −6? f(x) = x2 16x 60 f(x) = x2 − 16x 60 f(x) = x2 4x 60 f(x) = x2 − 4x 60
LiRa [457]

Answer:

Option A is correct

The function x^2+16x+60 has real zeroes at x =-10 and x =-6

Explanation:

Given: The real zeroes or roots are x = -10, and x = -6

To find the quadratic function of degree 2.

x^2- (\alpha+\beta)x + \alpha\beta =0 where α,β are real roots.   ....[1]

Here, α= -10  and β= -6

Sum of the roots:

α+β =  -10+(-6) = -10-6 = -16

Product of the roots:

αβ = (-10)(-6)= 60

Substitute these value in equation [1] we have;

x^2-(-16)x+60 = x^2+16x+60

Therefore, the quadratic function for the real roots at x =-10 and x =-6 ;

x^2+16x+60

8 0
3 years ago
Read 2 more answers
A square has an area of 225 m². What is the length of<br> the square’s diagonal?
Len [333]

Answer:

15

Step-by-step explanation:

15

8 0
3 years ago
Read 2 more answers
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