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3 years ago

Triangle BCD is equivalent AG=1.find the perimeter of BCD

Mathematics

1 answer:

Ymorist [56]3 years ago

4 0

AG=1 => BG=3 => CG=sqrt3 => CD = 2sqrt3 => perimeter = 3*CD= 6sqrt3

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B. Rob would like to create a triangle that is

Phantasy [73]

Answer:

$14y + 9$

Step-by-step explanation:

Perimeter of the given triangular above = sum of all its sides.

$= (y + 9) + 2y + (4y - 1) = y + 9 + 2y + 4y -1$

Collect like terms

$= y + 2y + 4y + 9 - 1$

$= 7y + 8$

If Bob creates a new triangle that is 7 less than twice of the perimeter of the triangle above, the expression of the new triangle would be:

$2(7y + 8) - 7$

Simplify

$2*7y + 2*8 - 7$

$14y + 16 - 7$

New perimeter = $14y + 9$

5 0

2 years ago

Is the following relation a function?<br><br> Yes or no

Zielflug [23.3K]

Answer:

yes

Step-by-step explanation:

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2 years ago

Find the slope(-1,-1),(2,-2)

Natali [406]

Answer:

$\huge\boxed{slope=-\dfrac{1}{3}}$

Step-by-step explanation:

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Substitute the coordinates of the given points (-1, -1) and (2, -2):

$m=\dfrac{-2-(-1)}{2-(-1)}=\dfrac{-2+1}{2+1}=\dfrac{-1}{3}=-\dfrac{1}{3}$

5 0

2 years ago

What is the answer 5i/(2+3i)^2

Nataly_w [17]

Simplify the following:5 i/(3 i + 2)^2
(3 i + 2)^2 = 4 + 6 i + 6 i - 9 = -5 + 12 i:(5 i)/12 i - 5
Multiply numerator and denominator of (5 i)/(12 i - 5) by 5 + 12 i:(5 i (12 i + 5))/((12 i - 5) (12 i + 5))
(12 i - 5) (12 i + 5) = -5×5 - 5×12 i + 12 i×5 + 12 i×12 i = -25 - 60 i + 60 i - 144 = -169:(5 i (12 i + 5))/-169
i (12 i + 5) = -12 + 5 i:(5 5 i - 12)/(-169)
Multiply numerator and denominator of (5 (5 i - 12))/(-169) by -1:Answer: (-5 (5 i - 12))/169

3 0

3 years ago

Needs help with algebra

Maslowich

Answer:

$4 {a}^{2} + 5b = 9b - 7c$

$=> 4 {a}^{2} + 7c = 9b - 5b$

$=> \frac{4 {a}^{2} + 7c }{4} = b$

option C

6 0

2 years ago