Answer: 423.11 m^2
Step by step explanation:
Area of a circle formula pi*r^2
First solve the area of the big circle
3.14*21^2=1384.74 m^2
Now find the are of the smaller circle
r=21-3.5=17.5
3.14*(17.5)^2=961.63 m^2
Now we can minus the small area off the big area to get the shaded area.
1384.74-961.63=423.11 m^2
So the area of the shaded region is 423.11 m^2
Answer:
B. <
Step-by-step explanation:
you dont even have to reduce the fractions to compare the decimals cause 5 is bigger then 4 off the bat.
Answer:
942 6/7 cm²
Step-by-step explanation:
Since O = Center of bigger circle, OA = Radius of bigger circle.
∴ Area of smaller circle - Area of bigger circle = Area of shaded part.
∴ Area of smaller circle = 22/7 × 10²
= 22/7 × 100
= 2200/7
= 314 2/7 cm²
∴ Area of bigger circle = 22/7 × 20 ²
= 22/7 × 400
= 1257 1/7 cm²
∴ Area of shaded part = 1257 1/7 - 314 2/7
= 942 6/7 cm²
Answer:
P(W|B) = 0.58
Step-by-step explanation:
The conditional probability formula tells you ...
P(W | B) = P(W&B) / P(B)
= 0.29/.050
= 0.58
Given that the triangle is dilated by factor 3, the image will be found as follows;
The object is at:
A(-7,-3), B(-3,-2), C(-4,-5)
when the image was enlarged the new coordinates will be:
A'=3(-7,-3)=(-21,-9)
B'=3(-3,-2)=(-9,-6)
C'=3(-4,-5)=(-12,-15)
since the image is centered at the point (-7,-6), the final point will be at:
A"=[(-21+-7),(-9+-6)=(-28,-15)
B''=[(-9+-7),(-6+-6)]=(-16,-12)
C''=[(-12+-7),(-15+-6)]=(-19,-17)
thus the coordinates of the final image are:
A''(-28,-15),B''(-16,-12),C''(-19,-17)
