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3 years ago

A polynomial p has zeros when I = 0.2 = -

Mathematics

1 answer:

Rainbow [258]3 years ago

5 0

Answer:

p(x) = (5x - 1) (x + 3)

Step-by-step explanation:

I apologize if I couldn't answer correctly, the question was a bit hard to understand because of the formatting.

Also I didn't see my answer in the list of answer choices but here it is:

if the polynomial has zeros at 0.2 and -3 the equation would have to be:

p(x)=(x-0.2)(x+3)

This is because plugging either of those numbers into the polynomial would cause it to equal 0.

(x-0.2) can be simplified by multiplying everything in the parenthesis by 5, getting rid of all of the decimals, making the final answer:

p(x) = (5x - 1) (x + 3)

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I NEED HELP!! please show all work

PtichkaEL [24]

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Drop the exponents:

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Expand the right side:

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Move the terms containing x to the left side and factor out x :

$\implies 5x \log 4 - x \log 3 = - 2 \log 3$

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Solve for x by dividing boths ides by 5 log(4) - log(3) :

$\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}$

You can stop there, or continue simplifying the solution by using properties of logarithms:

$\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }$

$\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }$

$\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}$

You can condense the solution further using the change-of-base identity,

$\implies \boxed{x = -\log_{\frac{1024}3}9}$

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Step-by-step explanation:

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